Don't pass formula
January 20th, 2011 at 3:55:01 PM
permalink
What is the equation for computing the don't pass flat bet?
January 20th, 2011 at 4:50:43 PM
permalink
You can probably find answers to most of your questions on the Wizard's Craps page: https://wizardofodds.com/craps
I invented a few casino games. Info:
http://www.DaveMillerGaming.com/ —————————————————————————————————————
Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁
January 21st, 2011 at 5:12:58 AM
permalink
I need this for the Don't Pass:
1.414% Calculation: The probability of winning on the come out roll is:
Pr (7) +pr (11) = 6/36 + 2/36 = 8/36.
The probability of establishing a point and then winning is pr(4)×pr(4 before 7) + pr(5)×pr(5 before 7) + pr(6)×pr(6 before 7) + pr(8)×pr(8 before 7) + pr(9)×pr(9 before 7) + pr(10)×pr(10 before 7) =
(3/36)×(3/9) + (4/36)×(4/10) + (5/36)×(5/11) + (5/36)×(5/11) + (4/36)×(4/10) + (3/36)×(3/9) =
(2/36) × (9/9 + 16/10 + 25/11) =
(2/36) × (990/990 + 1584/990 + 2250/990) =
(2/36) × (4824/990) = 9648/35640
The overall probability of winning is 8/36 + 9648/35640 = 17568/35640 = 244/495
thanks
1.414% Calculation: The probability of winning on the come out roll is:
Pr (7) +pr (11) = 6/36 + 2/36 = 8/36.
The probability of establishing a point and then winning is pr(4)×pr(4 before 7) + pr(5)×pr(5 before 7) + pr(6)×pr(6 before 7) + pr(8)×pr(8 before 7) + pr(9)×pr(9 before 7) + pr(10)×pr(10 before 7) =
(3/36)×(3/9) + (4/36)×(4/10) + (5/36)×(5/11) + (5/36)×(5/11) + (4/36)×(4/10) + (3/36)×(3/9) =
(2/36) × (9/9 + 16/10 + 25/11) =
(2/36) × (990/990 + 1584/990 + 2250/990) =
(2/36) × (4824/990) = 9648/35640
The overall probability of winning is 8/36 + 9648/35640 = 17568/35640 = 244/495
thanks
January 21st, 2011 at 8:42:16 AM
permalink
For Don't Pass, the probability of winning on the come out roll is:
Pr (2) +pr (3) = 1/36 + 2/36 = 3/36.
The probability of establishing a point and then winning is pr(4)×pr(7 before 4) + pr(5)×pr(7 before 5) + pr(6)×pr(7 before 6) + pr(8)×pr(7 before 8) + pr(9)×pr(7 before 9) + pr(10)×pr(7 before 10) =
(3/36)×(6/9) + (4/36)×(6/10) + (5/36)×(6/11) + (5/36)×(6/11) + (4/36)×(6/10) + (3/36)×(6/9) =
(12/36) × (3/9 + 4/10 + 5/11) =
(12/36) × (330/990 + 396/990 + 450/990) =
(12/36) × (1176/990) = 14112/35640
The overall probability of winning is 3/36 + 14112/35640 = 17082/35640 = 949/1980.
The probability of a push is pr (12) = 1/36, and the probability of losing = 244/495.
Check: 949/1980 + 1/36 + 244/495 = 1.
Pr (2) +pr (3) = 1/36 + 2/36 = 3/36.
The probability of establishing a point and then winning is pr(4)×pr(7 before 4) + pr(5)×pr(7 before 5) + pr(6)×pr(7 before 6) + pr(8)×pr(7 before 8) + pr(9)×pr(7 before 9) + pr(10)×pr(7 before 10) =
(3/36)×(6/9) + (4/36)×(6/10) + (5/36)×(6/11) + (5/36)×(6/11) + (4/36)×(6/10) + (3/36)×(6/9) =
(12/36) × (3/9 + 4/10 + 5/11) =
(12/36) × (330/990 + 396/990 + 450/990) =
(12/36) × (1176/990) = 14112/35640
The overall probability of winning is 3/36 + 14112/35640 = 17082/35640 = 949/1980.
The probability of a push is pr (12) = 1/36, and the probability of losing = 244/495.
Check: 949/1980 + 1/36 + 244/495 = 1.
