Baccarat 0 to 0 Tie
February 27th, 2024 at 9:46:28 AM
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I am trying to figure out how many possible combinations there are for a 6-card 0 to 0 tie that consists of 6 zero value cards; 8 deck Baccarat.
There are 128 Zero Value cards in a 8 deck shoe; 10s, Jack's, Queens, Kings
Currently, I have the probability as follows:
P(x)=(128÷416)×(127÷415)×(126÷414)×(125÷413)×(124÷412)×(123÷411) = 0.0007812503
First question, is that calculation above correct?
The main question, can I take P(x) times the total possible outcomes in a 8-deck shoe to get the answer I'm looking for? Or, is this a much more complicated problem?
Thanks!
There are 128 Zero Value cards in a 8 deck shoe; 10s, Jack's, Queens, Kings
Currently, I have the probability as follows:
P(x)=(128÷416)×(127÷415)×(126÷414)×(125÷413)×(124÷412)×(123÷411) = 0.0007812503
First question, is that calculation above correct?
The main question, can I take P(x) times the total possible outcomes in a 8-deck shoe to get the answer I'm looking for? Or, is this a much more complicated problem?
Thanks!
February 27th, 2024 at 10:28:42 AM
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Quote: KrazyKurtI am trying to figure out how many possible combinations there are for a 6-card 0 to 0 tie that consists of 6 zero value cards; 8 deck Baccarat.
There are 128 Zero Value cards in a 8 deck shoe; 10s, Jack's, Queens, Kings
Currently, I have the probability as follows:
P(x)=(128÷416)×(127÷415)×(126÷414)×(125÷413)×(124÷412)×(123÷411) = 0.0007812503
First question, is that calculation above correct?
The main question, can I take P(x) times the total possible outcomes in a 8-deck shoe to get the answer I'm looking for? Or, is this a much more complicated problem?
Thanks!
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I am not clear on what answer you are looking for. You already have the probability that the first 6 cards off the deck are among the ranks T,J,Q,K:
(128 choose 6)/(416 choose 6) = 0.00078125028
If just typed (128 choose 6)/(416 choose 6) into the google search bar to get this answer.
Gambling is a math contest where the score is tracked in dollars. Try not to get a negative score.
February 27th, 2024 at 10:45:46 AM
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I am trying to find the total number of possible combinations for a 6-card All Zero Value Tie.
February 27th, 2024 at 10:46:16 AM
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What is a combination? For example there are 8 king of diamond cards. Is each identical or distinct for counting combos? Does order matter for all three cards in a hand or just for the third card?
Or do you mean permutations?
Or do you mean permutations?
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
February 27th, 2024 at 12:05:29 PM
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If you mean permutations where every card is distinct and the order of each card matters then you just need the numerator of your probability equation.
128x127x126x125x124x124
If some of those permutations should be treated as “identical” (see my post above) then you need to find the right denominator as well.
128x127x126x125x124x124
If some of those permutations should be treated as “identical” (see my post above) then you need to find the right denominator as well.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
February 27th, 2024 at 12:10:53 PM
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You are missing multicard combos that add up to zero, such as:
64|73-K|K
or
12|12-7|7
64|73-K|K
or
12|12-7|7
So many better men, a few of them friends, are dead. And a thousand thousand slimy things live on, and so do I.
February 27th, 2024 at 12:13:41 PM
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Quote: gordonm888You are missing multicard combos that add up to zero, such as:
64|73-K|K
or
12|12-7|7
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I am not interested in those. I only care about All Zero Value Ties consisting of 6 cards.
So Player and Banker have 3 cards each, and those 3 cards are all Zero Value.
February 27th, 2024 at 12:19:31 PM
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Quote: unJonWhat is a combination? For example there are 8 king of diamond cards. Is each identical or distinct for counting combos? Does order matter for all three cards in a hand or just for the third card?
Or do you mean permutations?
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Let me see if I can explain this in a different way since I'm not an expert with statistics. Hopefully this will clear up my question.
In a 8 deck shoe there are 475,627,426,473,216 possible Tie combinations. I want to know out of those possible combinations, how many are a 0 to 0 Tie with all 6 cards being a Zero Value card.
Total combinations in a 8 deck Baccarat shoe are 4,998,398,275,503,360. This info can be found at /games/baccarat/basics/#eight-deck-analysis
February 27th, 2024 at 12:23:20 PM
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Never mind.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
February 27th, 2024 at 12:33:12 PM
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Quote: unJonNever mind.
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Did I not explain it well enough or is it too difficult lol?
February 27th, 2024 at 12:50:43 PM
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Quote: KrazyKurtQuote: unJonNever mind.
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Did I not explain it well enough or is it too difficult lol?
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No it’s all good. Your numbers indicate you are looking for permutations not combinations. So the answer you want is 128! / 122! = 3,905,000,064,000
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
February 27th, 2024 at 12:56:27 PM
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Quote: unJonQuote: KrazyKurtQuote: unJonNever mind.
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Did I not explain it well enough or is it too difficult lol?
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No it’s all good. Your numbers indicate you are looking for permutations not combinations. So the answer you want is 128! / 122! = 3,905,000,064,000
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WOW!!! That's awesome! Thanks man!!
Are you able to explain how the denominator is 122!?
February 27th, 2024 at 12:58:22 PM
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Or at least a website that explains that. I've been trying to figure this out for a couple days lol
February 27th, 2024 at 1:00:25 PM
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Quote: KrazyKurtOr at least a website that explains that. I've been trying to figure this out for a couple days lol
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It’s just:
128 x 127 x 126 x 125 x 124 x 123
ETA: you would get the same answer if you take the total permutations of all hands in an 8 deck shoe from your post above multiplied by the probability of getting a zero tie with all zeroes from your first post.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
