There are 128 Zero Value cards in a 8 deck shoe; 10s, Jack's, Queens, Kings

Currently, I have the probability as follows:

P(x)=(128÷416)×(127÷415)×(126÷414)×(125÷413)×(124÷412)×(123÷411) = 0.0007812503

First question, is that calculation above correct?

The main question, can I take P(x) times the total possible outcomes in a 8-deck shoe to get the answer I'm looking for? Or, is this a much more complicated problem?

Thanks!

Quote:KrazyKurtI am trying to figure out how many possible combinations there are for a 6-card 0 to 0 tie that consists of 6 zero value cards; 8 deck Baccarat.

There are 128 Zero Value cards in a 8 deck shoe; 10s, Jack's, Queens, Kings

Currently, I have the probability as follows:

P(x)=(128÷416)×(127÷415)×(126÷414)×(125÷413)×(124÷412)×(123÷411) = 0.0007812503

First question, is that calculation above correct?

The main question, can I take P(x) times the total possible outcomes in a 8-deck shoe to get the answer I'm looking for? Or, is this a much more complicated problem?

Thanks!

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I am not clear on what answer you are looking for. You already have the probability that the first 6 cards off the deck are among the ranks T,J,Q,K:

(128 choose 6)/(416 choose 6) = 0.00078125028

If just typed (128 choose 6)/(416 choose 6) into the google search bar to get this answer.

Or do you mean permutations?

128x127x126x125x124x124

If some of those permutations should be treated as “identical” (see my post above) then you need to find the right denominator as well.

64|73-K|K

or

12|12-7|7

Quote:gordonm888You are missing multicard combos that add up to zero, such as:

64|73-K|K

or

12|12-7|7

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I am not interested in those. I only care about All Zero Value Ties consisting of 6 cards.

So Player and Banker have 3 cards each, and those 3 cards are all Zero Value.

Quote:unJonWhat is a combination? For example there are 8 king of diamond cards. Is each identical or distinct for counting combos? Does order matter for all three cards in a hand or just for the third card?

Or do you mean permutations?

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Let me see if I can explain this in a different way since I'm not an expert with statistics. Hopefully this will clear up my question.

In a 8 deck shoe there are 475,627,426,473,216 possible Tie combinations. I want to know out of those possible combinations, how many are a 0 to 0 Tie with all 6 cards being a Zero Value card.

Total combinations in a 8 deck Baccarat shoe are 4,998,398,275,503,360. This info can be found at /games/baccarat/basics/#eight-deck-analysis

Quote:unJonNever mind.

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Did I not explain it well enough or is it too difficult lol?

Quote:KrazyKurtQuote:unJonNever mind.

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Did I not explain it well enough or is it too difficult lol?

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No it’s all good. Your numbers indicate you are looking for permutations not combinations. So the answer you want is 128! / 122! = 3,905,000,064,000

Quote:unJonQuote:KrazyKurtQuote:unJonNever mind.

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Did I not explain it well enough or is it too difficult lol?

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No it’s all good. Your numbers indicate you are looking for permutations not combinations. So the answer you want is 128! / 122! = 3,905,000,064,000

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WOW!!! That's awesome! Thanks man!!

Are you able to explain how the denominator is 122!?

Quote:KrazyKurtOr at least a website that explains that. I've been trying to figure this out for a couple days lol

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It’s just:

128 x 127 x 126 x 125 x 124 x 123

ETA: you would get the same answer if you take the total permutations of all hands in an 8 deck shoe from your post above multiplied by the probability of getting a zero tie with all zeroes from your first post.