How to calculate streaks

What is the correct way to calculate the odds of 9 consecutive losing outside roulette bets? The odds of losing on a single spin on black/red, even/odd, hi/low is 52.6%. If I plug .526 with a 150 series length (50 roulette spins with 3 events on each spin) and a streak of 9 into streak calculators online, I get 19.075%. However, if I go to a binomial distribution calculator (uiowa being my favorite) and enter n = 150, p = .0030822772 (.526 to the ninth), and an x value of 1, the chance of the .3% event happening >= 1 is 37.06%. Are either of these percentages correct?

The chance of 150 coin flips without a streak of nine heads is the 152nd Fibonacci number of the 9th order divided by 2^150. Use that to approximate even-money roulette bets, which are reasonably close to coin flips

Use a Markov chain to get the exact answer. Very easy to set up this scenario

One problem with what you are trying to do is, the three events on each spin aren't independent.

The probability of getting 9 losses in a row at least once somewhere in a run of 50 spins is about 6.2077%.
For 150 spins, using 10/19 instead of 0.526, I get 19.1821%.