May 8th, 2020 at 5:35:27 PM
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Standard Deviation for Even Chance bet,

EV ± ( Bet * 2 * √(n* p * q) )

Example WITHOUT La Partage,

18 ways I Win, 19 ways I Lose.

n = 37 spins

p = (18/37)

q = (1-p) = (19/37)

Bet = $5.00

EV = -$5.00 after 37 spins.

1 STD =

-$5.00 ± ( $5.00 * 2 * √(37*(18/37)*(19/37)) ) =

-$5.00 ± $30.4027025826

Between ≈ -$35.40>...<+$25.40

Example WITH La Partage,

18 ways I Win, 18 ways I Lose and 1 way to lose 0.5.

n = 37 spins

p = (18/37)

Probability of Loss = (18/37) + (0.5/37) = (18.5/37)????

OR is q still (1-p) = (19/37)

Bet = $5.00

EV = -$2.50 after 37 spins.

1 STD =

-$2.50 ± ( $5.00 * 2 * √(37*(18/37)*(18.5/37)) ) =

-$2.50 ± $30.00

Between = -$32.50>...<+$27.50

I know q = (1 - p) but does that change with the La Partage rule? If I use q = (1 - p) i get (19/37) for both examples above. But I also always assumed q = “probability of loss” so then I get (18.5/37) with La Partage. Maybe I shouldn’t assume. Haha!

I know the difference is very minor but I was just curious. Thanks!

EV ± ( Bet * 2 * √(n* p * q) )

Example WITHOUT La Partage,

18 ways I Win, 19 ways I Lose.

n = 37 spins

p = (18/37)

q = (1-p) = (19/37)

Bet = $5.00

EV = -$5.00 after 37 spins.

1 STD =

-$5.00 ± ( $5.00 * 2 * √(37*(18/37)*(19/37)) ) =

-$5.00 ± $30.4027025826

Between ≈ -$35.40>...<+$25.40

Example WITH La Partage,

18 ways I Win, 18 ways I Lose and 1 way to lose 0.5.

n = 37 spins

p = (18/37)

Probability of Loss = (18/37) + (0.5/37) = (18.5/37)????

OR is q still (1-p) = (19/37)

Bet = $5.00

EV = -$2.50 after 37 spins.

1 STD =

-$2.50 ± ( $5.00 * 2 * √(37*(18/37)*(18.5/37)) ) =

-$2.50 ± $30.00

Between = -$32.50>...<+$27.50

I know q = (1 - p) but does that change with the La Partage rule? If I use q = (1 - p) i get (19/37) for both examples above. But I also always assumed q = “probability of loss” so then I get (18.5/37) with La Partage. Maybe I shouldn’t assume. Haha!

I know the difference is very minor but I was just curious. Thanks!

Dane Peterson

May 9th, 2020 at 10:15:10 AM
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I don't think it's as easy as that. It's no longer an "even money bet" as there are three possible results.

There are now three probabilities involved:

p = the probability of a win of 1

q = the probability of a loss of 1

r = the probability of a loss of 1/2

p + q + r = 1

The mean M = p - q - r/2

The variance, which is the square of the SD, is:

p (1 - M)

Over N bets, the mean is nM, and the SD is √(N (p (1 - M)

There are now three probabilities involved:

p = the probability of a win of 1

q = the probability of a loss of 1

r = the probability of a loss of 1/2

p + q + r = 1

The mean M = p - q - r/2

The variance, which is the square of the SD, is:

p (1 - M)

^{2}+ q (-1 - M)^{2}+ r (-1/2 - M)^{2}Over N bets, the mean is nM, and the SD is √(N (p (1 - M)

^{2}+ q (-1 - M)^{2}+ r (-1/2 - M)^{2}))
May 9th, 2020 at 11:07:02 AM
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Thank you ThatDonGuy! I appreciate you taking the time to explain it.

Dane Peterson

May 9th, 2020 at 11:19:01 AM
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p is probability of success and q = 1 - p is the probability of failure. Q is applicable only if there are two possible outcomes: success or failure. La partage roulette has 3 possible outcomes.

However, we can reformat the bet into binary outcome bet and get a q value. The variance V of the game is .9795 and it’s return R is 73/74. 1 / (V/R^2 +1) = .4984 which is our new p value. The payout is R/P - 1 = .979 to 1. The q value is 1 - p = .5016. For evaluating your expected result and variance, this bet is statistically equivalent to the original bet.

Using round numbers, the new bet would be like having a wheel with 153 black, 153 red and 1 green pockets and you get paid .98 to 1 for a win on red or black. No partage

However, we can reformat the bet into binary outcome bet and get a q value. The variance V of the game is .9795 and it’s return R is 73/74. 1 / (V/R^2 +1) = .4984 which is our new p value. The payout is R/P - 1 = .979 to 1. The q value is 1 - p = .5016. For evaluating your expected result and variance, this bet is statistically equivalent to the original bet.

Using round numbers, the new bet would be like having a wheel with 153 black, 153 red and 1 green pockets and you get paid .98 to 1 for a win on red or black. No partage

It’s all about making that GTA

May 9th, 2020 at 11:29:00 AM
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Thanks Ace2! I appreciate the great explanation of changing it to a binary outcome.

Dane Peterson

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