picksixes
picksixes
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Joined: Nov 8, 2010
November 8th, 2010 at 12:25:54 PM permalink
Please help me! I posted in a few other forums, and nobody could answer this question!

A player deposited 100$ in his account.
He bets each time 10$
The chance of winning are 50%
He gets 1,85 times his money when winning.

On average, how many bets does he make before going broke?

Thank you
dwheatley
dwheatley
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Joined: Nov 16, 2009
November 8th, 2010 at 1:00:47 PM permalink
Simulation shows the average # of bets to be around 120-130 before you have less than $10 to bet.

This can be solved recursively, or using Markov chains.
Wisdom is the quality that keeps you out of situations where you would otherwise need it
MathExtremist
MathExtremist
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Joined: Aug 31, 2010
November 8th, 2010 at 3:03:20 PM permalink
Makes sense. The EV per bet is -$0.75, so $100/$0.75 is 133...
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice." -- Girolamo Cardano, 1563
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