37 roulette players at the same table

37 players, who each have a different favourite number gather round the same single zero roulette table.

The first day they each show up with $1000, and flat bet $1 a hand on their favourite number. As soon as they have more money than they started with they leave. What are the odds they will all make a profit? What are the odds 2 or more of them will lose all their money?

The second day they again show up at the same table with $1000 each and bet $1 a hand on their favourite numbers. However, this time they all stay until they all have less money than they came in with. What's the median and mean for how many rolls this would take?

These sound like questions from a probability and statistics class.

Quote: DRich

These sound like questions from a probability and statistics class.

Nope, just something I'm curious about. I just tried to phrase it as cleanly as possible.

Trick question, nobody’s favorite number is 0.

Quote: questionmaster

37 players, who each have a different favourite number gather round the same single zero roulette table.

you really mean an electronic version (maybe Rapid Roulette) as no table would ever allow 37 players to bet. not enough color chips.

and how many spins in a day?
I guess it could be max 1,920 (24*60*60/45)

question needs more explaining. too vague as posted.

Quote: 7craps

you really mean an electronic version (maybe Rapid Roulette) as no table would ever allow 37 players to bet. not enough color chips.

and how many spins in a day?
I guess it could be max 1,920 (24*60*60/45)

question needs more explaining. too vague as posted.

There's nothing vague about the question, median and mean are very clear terms that someone who has the ability to answer such a question would easily understand. If you want to be pedantic change it to "they all load up the same Live Dealer table at their preferred online casino", I just liked the way "gather together" sounded.