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(including the come out rolls of 2 or 3 which pay the Don't Pass).

Thanks in advance

it's close enough to a 50-50 chance to say the chances are one in 2^8, 1/256, for the purposes of martingale pondering

the chances are actually 244/495, which by the same crunching comes to one in 286.895 unless you want to go more decimals

the probability of winning the pass line (and losing the don't pass)Quote:LongshotWhat are the odds of a shooter passing the dice 8 straight decisions? In other words, if I was playing the Don't Pass line what are my odds of loosing 8 straight decisions.

(including the come out rolls of 2 or 3 which pay the Don't Pass).

Thanks in advance

is 244/495 (as another point out)

being that each 'game' played is an independent event, one just multiplies the probabilities out

a= (244/495)

x = a^8 = a*a*a*a* a*a*a*a

x = 12563730464589807616/3604471462609062890625 (to be exact)

or close to 0.00348559576

or about 1 in 286.895 (over the very next 8 games)

where each attempt is NOT 1 game/trial in length

the average number of games would be about 563.82 to see at least 8 pass line winners in a row

ON AVERAGE, HOW MANY TRIALS thread

a streak of at least 8 in a row has a higher probability of happening (at least once)

when more trials are attempted

Here the code is for 1000 pass line bets (bolded)

runs.r(8,1000,244/495)

> runs.r(8,8,244/495)

[1] 0.003485596

> runs.r(8,10,244/495)

[1] 0.007020483

> runs.r(8,20,244/495)

[1] 0.02465153

> runs.r(8,60,244/495)

[1] 0.09221244

> runs.r(8,100,244/495)

[1] 0.1550935

> runs.r(8,200,244/495)

[1] 0.2938944

> runs.r(8,500,244/495)

[1] 0.5878524

> runs.r(8,1000,244/495)

[1] 0.8319812

from:

https://sites.google.com/view/krapstuff/streaks

section 1r.

I think I know what you are up to with this information

starts with a M

and ends with

arty

interesting question

Because it allows you to bet money that doesn’t have to undergo the hazard of surviving the come out.Quote:LongshotI have an idea what they will do... They will change the table minimum from $10 to where I can't make 8 bets. The maximum listed on the table is $1000 bet. I don't lay odds, as once i have survived the come out roll, the odds are in my favor so why erase that by laying odds.

it's been around for centuries and no one ever got rich besides the casinos

starting at $5 min and making 8 bets, the last bet would be $640Quote:LongshotI have an idea what they will do... They will change the table minimum from $10 to where I can't make 8 bets. The maximum listed on the table is $1000 bet.

Marty style.

with $10 min the 8th bet would be $1280.

the 7th bet would be $640.

sounds thrilling!

I have seen many shooters do something like this,

7,7,11,7,7 on their 1st 5 rolls.

Now you are at $320 Dpass bet ($10 min table)

Point 6 and wins right away

Now you have a $640 bet out there and the shooter rolls a Craps 12 on the next come out roll.

'the waiting is the hardest part'

enjoy the ride

Quote:7crapsstarting at $5 min and making 8 bets, the last bet would be $640

Marty style.

with $10 min the 8th bet would be $1280.

the 7th bet would be $640.

sounds thrilling!

I have seen many shooters do something like this,

7,7,11,7,7 on their 1st 5 rolls.

Now you are at $320 Dpass bet ($10 min table)

Point 6 and wins right away

Now you have a $640 bet out there and the shooter rolls a Craps 12 on the next come out roll.

'the waiting is the hardest part'

enjoy the ride

So true. After the first bet of 10 bucks if it's a loser, I only go to $15.; which would allow me 8 bets before reaching the max... the final bet being $960... In 2 days playing off and on (I spent lots of hours in the sports room playing..watching races sports), my max bet never went past $120.... I know martingale is a loosing proposition because of the Table limit only... I profited about $200 or thereabouts.... The eye in the sky probably noticed and one of the boxmen called out $120 don't pass, like it was some big deal.. Table games for me are limited to hit and run, but it's getting me a comped room...