Baccarat odds / player streak

For Baccarat, How many times can 5 or more player wins happen, in multiple shoes, without exactly 4 player wins in a row??

Quote: boilrroom

For Baccarat, How many times can 5 or more player wins happen, in multiple shoes, without exactly 4 player wins in a row??

Welcome to the forum BR.
There is no limit.
It just gets a bit, well rather a lot, unlikely to keep happening as time progresses.

If you need some maths, I expect some Baccarat or maths experts will be along shortly.

Quote: boilrroom

For Baccarat, How many times can 5 or more player wins happen, in multiple shoes, without exactly 4 player wins in a row??

It depends on just what you mean by "5 or more player wins, without 4 player wins in a row." Can you give some examples?

BBPPPPPB , BBBPPPPPPPBBBB, PPP, B, PP, BPPPPPB If the player has a streak of 5 in a row, 6,7,8 9 or more , is counted as a 1 time event that there was not a streak of exactly 4 players in a row. Unlimited shoes can take place. I was just looking for the max times player can have a streak of 5 or more, before exactly 4 players happen. I have seen this happen 6 times. It doesnt have to be in a row or in the same shoe.

thanks for replying!

or how many shoes can take place without exactly 4 player wins in a row. (BPPPPB)

Quote: boilrroom

or how many shoes can take place without exactly 4 player wins in a row. (BPPPPB)

To either question..... The answer is "There is no limit". Just like there is no limit to how often you can flip a coin and get heads every time.

Quote: boilrroom

or how many shoes can take place without exactly 4 player wins in a row. (BPPPPB)

in a shoe one could get PPPPB to start the shoe and BPPPP to end the shoe. BPPPPB is most common.

Here is what I get by looking at 10 million 8 deck shoes
NO 4 run for Player = about 0.312 (close to 1 in 3)



for NO 4 run in X shoes in a row

no 4 run - shoe	prob	1 in
1	0.3122645	3.20
2	0.097509118	10.26
3	0.030448636	32.84
4	0.009508028	105.17
5	0.00296902	336.81
6	0.000927119	1,078.61
7	0.000289506	3,454.15
8	9.04026E-05	11,061.63
9	2.82295E-05	35,423.91
10	8.81508E-06	113,442.00
11	2.75264E-06	363,288.16
12	8.5955E-07	1,163,398.86
13	2.68407E-07	3,725,684.01
14	8.3814E-08	11,931,180.18
15	2.61721E-08	38,208,570.56
16	8.17263E-09	122,359,636.01
17	2.55202E-09	391,846,130.47
18	7.96906E-10	1,254,853,274.93
19	2.48845E-10	4,018,558,865.73
20	7.77056E-11	12,869,086,513.95
21	2.42647E-11	41,212,134,309.04

the average is about 0.660206398 shoes without a 4 run Player. Not much of a help there.

your other question is interesting but not practical to run a simulation without changing one already done.
I doubt any would find the time to do that 4U

still, interesting question. I guess you wait for a 4run Player streak and bet it does not make it to 5?
wait... you bet that the Player run will make it to 5 after waiting for a 4 run
wait...
could be fun
Sally