Winning on at least one payline
October 17th, 2018 at 3:19:06 PM
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Hi, I am trying to calculate probability of winning anything on at least one payline.
3 rows x 5 columns, 20 paylines.
All pay lines have length 5.
7 symbols, 7th is wild
no scatter
The way I tried it is under the spoiler.
Any help is appreciated.
Tried to calculate it as P(777) = p(777)*20 - ( p(777)^2+175*2/20/19*(p(777)-p(777)^2 )/ Lenght(777) ) * 190 + ( p(777)^3 + 294*2/20/19/18*(p(777)-p(777)^3)/ Lenght(777) ) *1140/2 -....+
175 - Sum of shared stops between all 20 paylines in combinations of two
190 - C(2, 20)
294 - Sum of shared stops between all 20 paylines in combinations of three
p(i) - probability of i-th winning event (777 - n71*n72*n73*(N4-n74)*N5 / (N1*N2*N3*N4*N5) )
Length(i) - length of i-th combination (777 - L = 3, 7777 - L = 4)
The shortest winnig combination has l = 3
I tried approximating till combination of shared stops between 7 paylines
I calculated this for all combinations, took a sum, but it wasn't even remotely close to simulation
Difference was more than 2 times.
3 rows x 5 columns, 20 paylines.
All pay lines have length 5.
7 symbols, 7th is wild
no scatter
The way I tried it is under the spoiler.
Any help is appreciated.
Tried to calculate it as P(777) = p(777)*20 - ( p(777)^2+175*2/20/19*(p(777)-p(777)^2 )/ Lenght(777) ) * 190 + ( p(777)^3 + 294*2/20/19/18*(p(777)-p(777)^3)/ Lenght(777) ) *1140/2 -....+
175 - Sum of shared stops between all 20 paylines in combinations of two
190 - C(2, 20)
294 - Sum of shared stops between all 20 paylines in combinations of three
p(i) - probability of i-th winning event (777 - n71*n72*n73*(N4-n74)*N5 / (N1*N2*N3*N4*N5) )
Length(i) - length of i-th combination (777 - L = 3, 7777 - L = 4)
The shortest winnig combination has l = 3
I tried approximating till combination of shared stops between 7 paylines
I calculated this for all combinations, took a sum, but it wasn't even remotely close to simulation
Difference was more than 2 times.
October 17th, 2018 at 4:24:42 PM
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Not nearly enough information.
I have a feeling the shape of the lines is important, as you have to count how many sets of results have more than one winning payline.
Also, what do you need for a win - 2? 3? 5? Does it depend on the symbol? (I assume lines have to start from the left reel.)
Are there just seven symbols per reel? Do they come up with equal probability?
I have a feeling the shape of the lines is important, as you have to count how many sets of results have more than one winning payline.
Also, what do you need for a win - 2? 3? 5? Does it depend on the symbol? (I assume lines have to start from the left reel.)
Are there just seven symbols per reel? Do they come up with equal probability?
October 17th, 2018 at 8:14:53 PM
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It matters how much the lines overlap and the minimum symbols for each win. Is there a wild symbol? Which reels have wilds? This is easiest done through simulation.
I heart Crystal Math.
October 17th, 2018 at 10:13:34 PM
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3,4,5 left to right
All reels have each of the 7 symbols at least ones
no scatter
1 wild (7)
"I have a feeling the shape of the lines is important, as you have to count how many sets of results have more than one winning payline." yes it is, i am calculating it as m(i) - amount of shared stops between i lines
m(2) = 175
I can copy-paste here all the 20 paylines, but is it realy needed? I am not asking to calculate it for me, I am asking how to do it, like an algorithm or formula for analytic solution via spreadsheet(excel)
All reels have each of the 7 symbols at least ones
no scatter
1 wild (7)
"I have a feeling the shape of the lines is important, as you have to count how many sets of results have more than one winning payline." yes it is, i am calculating it as m(i) - amount of shared stops between i lines
m(2) = 175
I can copy-paste here all the 20 paylines, but is it realy needed? I am not asking to calculate it for me, I am asking how to do it, like an algorithm or formula for analytic solution via spreadsheet(excel)
