Craps Payoff Formulas for House Odds and True Odds.

Is there some simple math formulas to quickly calculate Craps: the house payoffs for bets made with the house odds and then paid for true odds. This is so I can quickly determine how many chips I should lay down to bet certain numbers and also to double check the dealers payoffs to make sure I am getting what I should. Thank you.

Quote: clyffcarlock

... the house payoffs for bets made with the house odds and then paid for true odds. ....

I had some difficulty understanding this part of your question, so what I offer here may not be what you are asking for. I'll limit myself to the topic of how many chips to include in your bet and leave the rest to someone else. With the exception of those few craps tables with minimums of less than $5, this should work for you. All of the following must be adjusted to comply with minimums greater than $5.

Pass, come, don't pass, don't come, and field bets in increments of $5. Place bets in increments of $5 except in increments of $6 for bets on 6 and 8. I've never made a lay bet, so I will leave that and buy bets for someone else to discuss.

Pass line and come bet odds bets (usually) in increments of $5, always an even number for pass/come odds bets on points of 5 and 9, and a maximum odds bet as specified for the particular table/casino, usually a multiple of the pass/come bet you made. Don't pass and don't come odds bets work out easiest if they are six times the don't pass/come bet.

Most proposition bets can be any amount from $1 to the maximum allowed. Horn bets in multiples of $4 and horn-high bets in multiples of $5.

I probably left something out, and I apologize if this response is trivial and not what you meant.

Edit: as for forumulae, payouts for place bets are 7 to 6 on six and eight, 7 to 5 on five and nine, and 9 to 5 on four and ten. Payouts for pass/come odds bets are 6 to 5 on six and eight, 3 to 2 on five and nine, and 2 to 1 on four and ten. Invert those for payouts on don't odds bets. Again, sorry if this is not what you were asking for.

your question in a bit confusing (house odds????) but if you are asking about putting odds behind your passline bet, this might help/

6&8..........units of 5 because every 5 wins 6
5&9.........units of 2 because every 2 wins 3
4&10........units of 1 because every 1 wins 2

Quote: appistappis

your question in a bit confusing (house odds????) but if you are asking about putting odds behind your passline bet, this might help/

6&8..........units of 5 because every 5 wins 6
5&9.........units of 2 because every 2 wins 3
4&10........units of 1 because every 1 wins 2

House odds are also known as house payoffs. Pretty much there are house odds and true odds (it's how house edge is calculated).

And flip it for lay odds.
Increments of 6 for 6/8.
Increments of 3 for 5/9.
Increments of 2 for 4/10.

House odds on lay bets (opposite of place bets) are weird and must be in high increments. This is posted on the wizards site, although I have no idea off the top of my head.

again, I have been a craps dealer for 35 years and I have never heard the term house odds or house payoffs.....if you mean lay bets 'are weird and must be in high increments'???????...........I will guess you are talking the min amount to lay bet.

25 no 6/8
31 no 5/9
41 no 4/10

i meant the house payoff with out putting odds behind the pass line. like, placing the 6 or 8, 5 or 9, 4 or 10. but i wanted to know in general is there any simple math formula/equation that i could use to figure out how much money to bet which ever numbers i want or how to figure out if the payouts to me from the dealers were correct. thank you.

if you mean place bets.....on the 6&8 every 6 bucks you bet wins 7
.....................................on the 5&9 every 5 bucks you bet wins 7.
....................................on the 4&10 every 5 bucks you bet wins 9...........when your bet gets to 20, then you buy yhe 4&10