On pick #22 (for instance), will the green, blue, orange, etc. all have the same payout or do they differ from each other?
Some random situation for next colour bet:
bet on blue (6 balls remaining): x6.15
bet on green (8 balls remaining): x4.61
bet on violet (6 balls remaining): x6.15
bet on red (6 balls remaining): x6.15
bet on orange (7 balls remaining): x5.27
bet on grey (8 balls remaining): x4.61
For "next ball" bet it's always like this: (remaining number of balls - 1)
So for example, if 10 balls were already drawn and I bet for next ball, my odds will be x37 (48 balls total - 10 drawn = 38 remaining. 38-1=37), so If I bet $1 I will get $37.
Betting on colour will not have the same payout, but betting on ball number will have the same payout.
So for example, if we are on pick #22 and:
4 blue balls were drawn,
4 green balls were drawn,
4 violet balls were drawn,
4 red balls were drawn,
5 orange balls were drawn
0 grey balls were drawn
so in total, 21 balls drawn, we have the same odd for betting on any number (regardless number ball's colour), we have 48-21-1=x26 payout for that bet. So if we bet on the ball "3 blue" we have same odds as betting on "45 grey".
But betting on next colour we will have different odds.
Can we combine two things like colour and parity to get most likely next number? For above example, let's assume that in 21 balls from the quote above ^ %70 of drawn balls was odd. Can we make next bet on every GREY EVEN ball? Will it increase chance? Or something like that.