September 30th, 2010 at 12:38:35 PM
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Can 6 be taken as a mean average of the ace, ie midway between 1 and 13?
If so, then 2 3 4 5 6 7 8 9 10 10 10 10 + 6 = 91 for the value of deck
91 divided by 13 cards
=
7.
Is 7 the average value likely to arise?
Is 3 cards on average more likely to result in 21 anyway?
thanks for looking!
blackorange
If so, then 2 3 4 5 6 7 8 9 10 10 10 10 + 6 = 91 for the value of deck
91 divided by 13 cards
=
7.
Is 7 the average value likely to arise?
Is 3 cards on average more likely to result in 21 anyway?
thanks for looking!
blackorange
September 30th, 2010 at 1:17:08 PM
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Since it will more often be used as an 11-count card than a 1-count, I would think that the mean would be more like 8. If it's initially dealt with a 9, 10, J, Q, or K, it will be counted as 11; with a 7 or 8, it will almost always be counted as 11; with another Ace, it will be counted as 11 (even if it's split and dealt a deuce). And even if it's dealt as part of A2-A6, it will often eventually be counted as 11 rather than 1.
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