Single zero roulette odds of the longest sequence of spins before the repeat of a previous number?

I assume it would be impossible for there to be 37 different numbers to appear consecutively. If I am right does anyone know the the correct math to calculate what would be maximum number of spins before a repeated number must or should occur? Any an all help or comments appreciated. Thanks, cheers: bellbiz

Quote: bellbiz

I assume it would be impossible for there to be 37 different numbers to appear consecutively.

I read somewhere that if the number of roulette wheels
stayed constant in the world, the numbers would appear
consecutively on one of them every 20 million years or
so. Give or take..

Quote: bellbiz

I assume it would be impossible for there to be 37 different numbers to appear consecutively. If I am right does anyone know the the correct math to calculate what would be maximum number of spins before a repeated number must or should occur? Any an all help or comments appreciated. Thanks, cheers: bellbiz

There is no -must- in a random string. Just more and more likely to occur. So what do you mean by 'should' greater than a 50% chance? 80%? 99%?

Quote: bellbiz

I assume it would be impossible for there to be 37 different numbers to appear consecutively. If I am right does anyone know the the correct math to calculate what would be maximum number of spins before a repeated number must or should occur? Any an all help or comments appreciated. Thanks, cheers: bellbiz

My calculation puts it at 1:13763753091226345046315979581580902400000000.

It is possible to have all 37 numbers appear without a repeat, therefore the maximum is 37. The 37 numbers do not have to be consecutive.
Your assumption is totally false, all 37 can appear w/o a repeat.

Cheers: Thanks Bob

Thanks Cess

HaHa - it is 6pm and time for all little boys to go to bed now! :-) G'night.

Quote: Avenger803

My calculation puts it at 1:13763753091226345046315979581580902400000000.

So far, this has been the only explicit answer to this question, but it is in the wrong units. The inquirer has asked for the maximum number of spins and the answer is in the form of an odds ratio. One learns in school that credit is not given for merely the answer if the method of calculation is not given

Logically, no question is being asked. The second sentence starts "If I am right..." referring to the first sentence, however the first sentence is wrong. It is perfectly possible for all 37 numbers to be different in 37 spins, however it is extremely unlikely. the odds that all numbers will appear consecutively are 1:37³⁷ = 1:1055513496E58. If we merely require that all numbers be different but may be in any order we reduce the odds by the number of ways 37 numbers may be arranged, which is 37! = 1.376375309E43.

If we ignore the fact that the first sentence is wrong and treat the question as "What would be the maximum number of spins before a repeated number must appear?" the answer is that there is no maximum but there is a minimum and that number is 38.

Quote: puzzlenut

If we ignore the fact that the first sentence is wrong and treat the question as "What would be the maximum number of spins before a repeated number must appear?" the answer is that there is no maximum but there is a minimum and that number is 38.

Technically, it's 37. It's single 0 roulette and your specification asks for the number of spins BEFORE a repeated number must appear. The repeat is on the 38th spin:-)

rdw4potus If you want to be picky, you spin the wheel before the ball drops, so the repeat number doesn't come up until after the 38th spin. Have you checked the math? Is it correct?