January 20th, 2013 at 3:17:43 PM
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Hi Wizard,
Your websites are chalked full of great information, I saw another posting stating, the odds of both the player and dealer receiving any 9 high in the same hand in Pai Gow Poker is about 26.4 million to 1.
How do you determine the probability that both the player and dealer are dealt a queen high in the same hand?
Given that a Q high Pai Gow
Combinations of getting any queen high = 2719500/154,143,080 = Probability = 0.017643
Thanks for the help, Mike from Cali
Your websites are chalked full of great information, I saw another posting stating, the odds of both the player and dealer receiving any 9 high in the same hand in Pai Gow Poker is about 26.4 million to 1.
How do you determine the probability that both the player and dealer are dealt a queen high in the same hand?
Given that a Q high Pai Gow
Combinations of getting any queen high = 2719500/154,143,080 = Probability = 0.017643
Thanks for the help, Mike from Cali
January 20th, 2013 at 3:45:53 PM
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Pai Gow hands facing pai gow hands are relatively rare.
The queen high is about 1 in 58, so it is one is 3,300 or so, less often because a queen and lower cards are consumed by the other hand.
The queen high is about 1 in 58, so it is one is 3,300 or so, less often because a queen and lower cards are consumed by the other hand.
Beware of all enterprises that require new clothes - Henry David Thoreau. Like Dealers' uniforms - Dan.