A 23-team, $100 college football parlay math question
Poll
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3 members have voted
October 25th, 2012 at 1:18:23 PM
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What a day! A man’s 23-team, $100 college football parlay paid $25,772 at BetOnline.ag
This better picked one underdog out of a 23 game parlay. Hypothetically, if he picked no underdogs, and all 23 games had the same odds, then what would that odd to return the same amount of money?
Let people choose ranges in poll for a while, before giving exact answer
Odds in bet
-300
-780
-780
-660
-205
-165
-940
-260
-500
-1100
-350
-1300
-245
-1300
-880
+125 <===== only underdog bet
-175
-1300
-340
-675
-400
-380
-310
This better picked one underdog out of a 23 game parlay. Hypothetically, if he picked no underdogs, and all 23 games had the same odds, then what would that odd to return the same amount of money?
Let people choose ranges in poll for a while, before giving exact answer
Odds in bet
-300
-780
-780
-660
-205
-165
-940
-260
-500
-1100
-350
-1300
-245
-1300
-880
+125 <===== only underdog bet
-175
-1300
-340
-675
-400
-380
-310
October 25th, 2012 at 3:47:46 PM
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I have no idea (guessed -350 ~ -400) but I don't even know how to begin calculating fair odds for that guy's bet. What was the juice on his bet?
"Dice, verily, are armed with goads and driving-hooks, deceiving and tormenting, causing grievous woe." -Rig Veda 10.34.4
October 25th, 2012 at 4:06:39 PM
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If I calculated it correctly, I think the answer is:
On the other hand, I could be way off too.
-366 (-366.28415 to be exact)
On the other hand, I could be way off too.
October 25th, 2012 at 4:25:08 PM
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Too bad he bet it at Betonline. They have a long history of not paying players.
Google search for Betonline payment issues
Google search for Betonline payment issues
