What are the odds of hitting at least tens full of nines and getting beat by a better hand?

What are the odds of hitting tens full of nines or better and getting beat by a better hand in Texas Hold 'em? Both hole cards must play in both hands. I play in a game that has a bad beat structured this way, and I'm just wondering how often it can be expected to be hit. I could not find this information anywhere else, and I don't know how to do the math, so I appreciate anyone's help. Thanks!

The Wizard has a page on bad beat jackpots you can check. According to that, the odds of it hitting at jacks full or better are 0.00015708 (that's seeing it at a full table; being the loser is a tenth that), or about 1 in 6366, and realistically, it's probably lower than even that due to the chance of not making the river.

Thanks for the response! I did view the page on bad beat jackpots, but I think those odds are for a full house getting beat by quads or better. The game I play in allows full house beat by full house to qualify, as long as the losing hand is at least tens full of nines. I know any odds I might be able to find will be a little off, because, like you said, sometimes you will not see all the cards and whatnot. But I just want to know the odds of this scenario occurring at a full table when nobody folds and all hands go to showdown. Can you think of anywhere else I could find this out? Thanks again for your help!