Probabability of dealing 9 cards in a single deck with no pair or better?
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July 14th, 2012 at 10:40:47 AM
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DUHHIIIIIIIII HEARD THAT!
July 14th, 2012 at 12:12:21 PM
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The probability that the second card doesn't pair the first = 48/51
The probability that the third card doesn't pair either of the first two = 44/50
The probability that the fourth card doesn't pair either of the first three = 40/49
and so on
The probability that none of the nine cards form a pair is
48/51 x 44/50 x 40/49 x 36/48 x 32/47 x 28/46 x 24/45 x 20/44 x 16/43
which is about 1/52.75
...but that wasn't what you asked; you asked about "pair or better", and my answer doesn't take into account straights or flushes.
The probability that the third card doesn't pair either of the first two = 44/50
The probability that the fourth card doesn't pair either of the first three = 40/49
and so on
The probability that none of the nine cards form a pair is
48/51 x 44/50 x 40/49 x 36/48 x 32/47 x 28/46 x 24/45 x 20/44 x 16/43
which is about 1/52.75
...but that wasn't what you asked; you asked about "pair or better", and my answer doesn't take into account straights or flushes.
July 14th, 2012 at 2:35:20 PM
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July 16th, 2012 at 4:31:47 PM
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Quote: miplethttps://wizardofodds.com/games/poker/
37,564,800 / 15,820,024,220
The link is right, but you used the wrong table.
Should be (69,788,040 / 3,679,075,400)
July 16th, 2012 at 6:10:37 PM
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DUHHIIIIIIIII HEARD THAT!
