What I normally see or hear is people saying this:
Bet 5, if lose bet 10 if lose bet 20 if lose bet 40...although this "sounds" right, I do not believe it is...
I think the actual progression would be this:
Bet 5, if lose bet 10, if lose bet 15 (to account for the first 5 you lost), if lose bet 30, if lose bet 60...
I know it only makes a slight difference but that's how I see it...
The difference is this:
With the normal Martingale, when you eventually win all your losses back, you're ahead $5 (or whatever the starting unit was).
With your method, you only win back the losses.
I.E. With your method, you HAVE to have at least two wins in a row to ever come out ahead.
anyway it goes like this: take a chess board and place a penny on the first square, then keep doubling it, 2c, 4c, 8c, 16c, blah blah anyone can see you soon get to dollars. So the question is, once you reach the last square, what is the correct answer?
*most people would have the money to place there, or
*only Bill Gates or his equal would have the money to place there, or
*no one in the world would have enough money to place there
Quote: aceofspades
I think the actual progression would be this:
Bet 5, if lose bet 10, if lose bet 15
Thats a D'alambert progression.
Quote: rainmanThe martinstinkle people need to consider that you cant keep wagering 100 to win 5 or whatever it ends up. you always risk way more than you win. The risk reward is wacked in these systems.
But...but...you're only really "risking" the money if you can't make the next bet following a loss! Otherwise you can just sell a kidney or two and re-double down on the next bet!
Quote: aceofspadesI know Martingale is a fallacy but I always had pondered this question (which is perhaps best answered by the mathematically inclined mind of the WIZARD)
What I normally see or hear is people saying this:
Bet 5, if lose bet 10 if lose bet 20 if lose bet 40...although this "sounds" right, I do not believe it is...
It is. This process means you win a net of 5 anytime you win Net Win is if the bet wins, net loss is if it doesn't.
Bet | Total Loss so far | Net Win | Net Loss |
5 | 0 | 5 | -5 |
10 | -5 | 5 | -15 |
20 | -15 | 5 | -35 |
40 | -35 | 5 | -75 |
... | ... | ... | ... |
Quote:
I think the actual progression would be this:
Bet 5, if lose bet 10, if lose bet 15 (to account for the first 5 you lost), if lose bet 30, if lose bet 60...
I know it only makes a slight difference but that's how I see it...
This scheme doesn't make a profit on every win.
Bet | Total Loss so far | Net Win | Net Loss |
5 | 0 | 5 | -5 |
10 | -5 | 5 | -15 |
15 | -15 | 0 | -30 |
30 | -30 | 0 | -60 |
... | ... | ... | ... |
Quote: DJTeddyBearI think the answer to this riddle is D. Only Bill Gates, plus several of his friends, combined, might have enough money to cover it.
About 92 quadrillion bucks? I don't think so :)
If you had this amount of money in $100 bills, stacked one on top of the other, the height of the stack would be about 100 million kilometers (about 2/3 of a distance from Earth to Sun).
Quote: thecesspitIt is. This process means you win a net of 5 anytime you win Net Win is if the bet wins, net loss is if it doesn't.
Bet Total Loss so far Net Win Net Loss 5 0 5 -5 10 -5 5 -15 20 -15 5 -35 40 -35 5 -75 ... ... ... ...
This scheme doesn't make a profit on every win.
Bet Total Loss so far Net Win Net Loss 5 0 5 -5 10 -5 5 -15 15 -15 0 -30 30 -30 0 -60 ... ... ... ...
I suppose I misunderstood Martingale - I thought the goal of Martingale was always get back to even to begin starting over again - now that I know I will come out ahead $5 I am going to call Bill Gates and tell him the EV on a Martingale is in our favor (maybe he will let me keep $2.50)
Quote: aceofspades
I suppose I misunderstood Martingale - I thought the goal of Martingale was always get back to even to begin starting over again - now that I know I will come out ahead $5 I am going to call Bill Gates and tell him the EV on a Martingale is in our favor (maybe he will let me keep $2.50)
I don't know how the second clause follows. The EV on a Martingale is never in your favour if each individual bet is not in your favour.
Quote: thecesspitI don't know how the second clause follows. The EV on a Martingale is never in your favour if each individual bet is not in your favour.
I was being sarcastic...
Oh. I must have slipped a digit or two. I was thinking around $10 trillion.Quote: weaselmanQuote: DJTeddyBearI think the answer to this riddle is D. Only Bill Gates, plus several of his friends, combined, might have enough money to cover it.
About 92 quadrillion bucks? I don't think so :)
Quote: aceofspadesI was being sarcastic...
Sorry, flew straight over my head....
Certainly even if the "mill" was resurrected as currency and that was your starting point, no one.... not even any nation on earth... could come up with the money.
Quote: FourFiveFaceKinda unrelated, but has anyone ever tried anti-martingale (assuming you're not already down)? Of course, no betting system works in the long-run and all that, but at least you don't go broke with this one. Then again, "house money" is, in truth, "your money", but we all know that most people don't think that way.
Some betting systems can be good in the SHORT run. I don't care if they won't work in the long run, I'm just trying to win a little bit right now. Just last night I was playing Blackjack, which I NEVER do, but I was ahead from craps. I bought in for $80, starting with $10 bet, pressing five after each win, pressing by $10 after the $30 bet. In one shoe I won $115, tipped 10 and walked away..
A little later in the night I started with $55, was all in with $15, won that hand, and won a few more, eventually hit a $40 blackjack, then got up to $75. Had 16 against 10, so surrendered. Walked away with $150, $95 ahead.
Positive count or trying to cool down heat by putting up a dumb bet.