777
777
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October 7th, 2015 at 11:53:51 AM permalink
What is the odds of hitting all doubles (1&1, 2&2, 3&3, 4&4, 5&5, and 6&6) before hitting 7 in craps?
miplet
miplet
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October 7th, 2015 at 12:40:25 PM permalink
Quote: 777

What is the odds of hitting all doubles (1&1, 2&2, 3&3, 4&4, 5&5, and 6&6) before hitting 7 in craps?


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ThatDonGuy
ThatDonGuy
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October 7th, 2015 at 12:49:57 PM permalink
Well,...

The only rolls that matter are 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. Each one is equally likely.

You have to do six things in order, in order to win:
1. Roll one of the six doubles before rolling one of the six sevens; the probability of this is 6/12, or 1/2.
2. Roll one of the five remaining doubles before rolling one of the six sevens; the probability of this is 5/11.
3. Roll one of the four remaining doubles before rolling one of the six sevens; the probability of this is 4/10, or 2/5.
4. Roll one of the three remaining doubles before rolling one of the six sevens; the probability of this is 3/9, or 1/3.
5. Roll one of the two remaining doubles before rolling one of the six sevens; the probability of this is 2/8, or 1/4.
6. Roll the one remaining double before rolling one of the six sevens; the probability of this is 1/7.

The total probability = 1/2 x 5/11 x 2/5 x 1/3 x 1/4 x 1/7 = 1 / 924.

Ibeatyouraces
Ibeatyouraces
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October 7th, 2015 at 12:54:06 PM permalink
I smell a new side bet brewing...
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777
777
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October 7th, 2015 at 1:05:12 PM permalink
All of the above... :-)
Paradigm
Paradigm
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October 7th, 2015 at 2:42:59 PM permalink
Is the concept different than Double D from 2012?

Double D

Look for Double D in the right hand margin list.
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