October 7th, 2015 at 11:53:51 AM
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What is the odds of hitting all doubles (1&1, 2&2, 3&3, 4&4, 5&5, and 6&6) before hitting 7 in craps?
October 7th, 2015 at 12:40:25 PM
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Quote: 777What is the odds of hitting all doubles (1&1, 2&2, 3&3, 4&4, 5&5, and 6&6) before hitting 7 in craps?
Are you a "give me a fish" or a "teach me how to fish" type of person?
“Man Babes” #AxelFabulous
October 7th, 2015 at 12:49:57 PM
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Well,...
The only rolls that matter are 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. Each one is equally likely.
You have to do six things in order, in order to win:
1. Roll one of the six doubles before rolling one of the six sevens; the probability of this is 6/12, or 1/2.
2. Roll one of the five remaining doubles before rolling one of the six sevens; the probability of this is 5/11.
3. Roll one of the four remaining doubles before rolling one of the six sevens; the probability of this is 4/10, or 2/5.
4. Roll one of the three remaining doubles before rolling one of the six sevens; the probability of this is 3/9, or 1/3.
5. Roll one of the two remaining doubles before rolling one of the six sevens; the probability of this is 2/8, or 1/4.
6. Roll the one remaining double before rolling one of the six sevens; the probability of this is 1/7.
The total probability = 1/2 x 5/11 x 2/5 x 1/3 x 1/4 x 1/7 = 1 / 924.
The only rolls that matter are 1-1, 2-2, 3-3, 4-4, 5-5, 6-6, 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. Each one is equally likely.
You have to do six things in order, in order to win:
1. Roll one of the six doubles before rolling one of the six sevens; the probability of this is 6/12, or 1/2.
2. Roll one of the five remaining doubles before rolling one of the six sevens; the probability of this is 5/11.
3. Roll one of the four remaining doubles before rolling one of the six sevens; the probability of this is 4/10, or 2/5.
4. Roll one of the three remaining doubles before rolling one of the six sevens; the probability of this is 3/9, or 1/3.
5. Roll one of the two remaining doubles before rolling one of the six sevens; the probability of this is 2/8, or 1/4.
6. Roll the one remaining double before rolling one of the six sevens; the probability of this is 1/7.
The total probability = 1/2 x 5/11 x 2/5 x 1/3 x 1/4 x 1/7 = 1 / 924.
October 7th, 2015 at 12:54:06 PM
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I smell a new side bet brewing...
DUHHIIIIIIIII HEARD THAT!
October 7th, 2015 at 1:05:12 PM
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All of the above... :-)