danepeterson
danepeterson
Joined: Apr 23, 2012
  • Threads: 7
  • Posts: 28
March 2nd, 2013 at 3:02:22 PM permalink
I play roulette at Barona Casino in San Diego all the time. I noticed on wizardofodds that it states on this page that the house edge is 2.78%:

http://wizardofodds.com/games/roulette/

It states "Best in California: It is my understanding that the only single-zero roulette in California is at the Barona casino, with a house edge of 2.78%."

but a link to this page shows a table with a house edge of 2.703%

http://wizardofodds.com/games/roulette/san-diego-county/

Can someone explain this difference in the numbers? I get 2.703% with this math:

(-1*(36/37)) + (35*(1/37)) = 0.027027027027 or 2.703%

Am I doing something wrong? How did you calculate the 2.78%???

Also, Barona's iTables have the La Partage rule on all even money bets. How would I calculate that?

(-0.5*(1/37)) + (-1*(35/37)) + (35*(1/37)) = 0.0135135135 or 1.35% ???

Thanks.
Wizard
Administrator
Wizard
Joined: Oct 14, 2009
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March 2nd, 2013 at 3:32:01 PM permalink
The 2.78% was a typo, it should have been 2.70%. Thanks for the correction.

For La Partage roulette, the expected return on even money bets is (18/37)*1 + (18/37)*-1 + (1/37)*(-1/2) = -1.35%. So, the house edge is +1.35%.
It's not whether you win or lose; it's whether or not you had a good bet.
danepeterson
danepeterson
Joined: Apr 23, 2012
  • Threads: 7
  • Posts: 28
March 2nd, 2013 at 4:45:50 PM permalink
Thanks!

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