January 20th, 2012 at 6:50:35 PM
permalink
at a baccarat game you would have met 10 loss in a row if we dont calculate banker / player percentage that would be chances of 1/1024
so roughly straight loss 10 would = 1 / 1024
however these is a situation call net loss
any wins can be throw in to your 10 loss, for example:
L L L L L L L L L W L L
could also be
L L L L L L L L W W L L L L
L W W W L L L L L L L L L L L L
combine all the possibility
I figured out that net loss 10 in a row would be = 1 / 512
can anybody help me verifying my calculation please?
so roughly straight loss 10 would = 1 / 1024
however these is a situation call net loss
any wins can be throw in to your 10 loss, for example:
L L L L L L L L L W L L
could also be
L L L L L L L L W W L L L L
L W W W L L L L L L L L L L L L
combine all the possibility
I figured out that net loss 10 in a row would be = 1 / 512
can anybody help me verifying my calculation please?