October 7th, 2011 at 10:34:30 PM
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Hi all
I am sure someone can help me with maths for this.
Say I play 6 numbers on a single zero roulette wheel.
What is the calculation that one of the six numbers will hit within 10 spins and 20 spins
Thanks in advance
I am sure someone can help me with maths for this.
Say I play 6 numbers on a single zero roulette wheel.
What is the calculation that one of the six numbers will hit within 10 spins and 20 spins
Thanks in advance
October 8th, 2011 at 7:48:11 AM
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Quote: PandoHi all
I am sure someone can help me with maths for this.
Say I play 6 numbers on a single zero roulette wheel.
What is the calculation that one of the six numbers will hit within 10 spins and 20 spins
Thanks in advance
There is a nice table already populated with data in Nope27's Blog. It shows probabilities for "at least 1" hit.
The top of the last table has the formulas
Table 3 Nope27 Blog
Answers:
at least 1 hit in 10 spins: 82.955%
at least 1 hit in 20 spins: 97.095%
Or if you are looking for exactly 1 hit and not at least 1
exactly 1 hit in 10 spins: 32.991%
exactly 1 hit in 20 spins: 11.247%
I would say this is a binomial distribution.
One can also use the BINOMDIST() function in Excel
Exact probability:
=BINOMDIST(1,10,6/37,0) 10 spins
=BINOMDIST(1,20,6/37,0) 20 spins
At least 1 probability:
=1-BINOMDIST(0,10,6/37,0) 10 spins
=1-BINOMDIST(0,20,6/37,0) 20 spins
Hope this helps
winsome johnny (not Win some johnny)
October 8th, 2011 at 7:56:04 AM
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This sort of thing is easier to figure out from the other direction.
I.E. What's the odds that any of the other 31 numbers are the numbers that come up in each of the next 10 spins. Then subtract that from 1.
( 31 / 37 ) ^ spins :
The 31/37 Odds columns show the odds of never hitting one of your six numbers in that many spins.
The 6/37 Odds columns show the odds of having hit it at least once in that many spins. It's just 1 minus the 31/37 odds.
Note that the items in bold are rounding errors. The odds will never equal 0% or 100%.
I.E. What's the odds that any of the other 31 numbers are the numbers that come up in each of the next 10 spins. Then subtract that from 1.
( 31 / 37 ) ^ spins :
Spins | 31/37 Odds | 1 in … | 6/37 Odds | 1 in … | ||
---|---|---|---|---|---|---|
1 | 83.78% | 1.19 | 16.22% | 6.17 | ||
2 | 70.20% | 1.42 | 29.80% | 3.36 | ||
3 | 58.81% | 1.70 | 41.19% | 2.43 | ||
4 | 49.28% | 2.03 | 50.72% | 1.97 | ||
5 | 41.29% | 2.42 | 58.71% | 1.70 | ||
6 | 34.59% | 2.89 | 65.41% | 1.53 | ||
7 | 28.98% | 3.45 | 71.02% | 1.41 | ||
8 | 24.28% | 4.12 | 75.72% | 1.32 | ||
9 | 20.34% | 4.92 | 79.66% | 1.26 | ||
10 | 17.05% | 5.87 | 82.95% | 1.21 | ||
15 | 7.037% | 14.21 | 92.96% | 1.08 | ||
20 | 2.905% | 34.42 | 97.09% | 1.03 | ||
25 | 1.199% | 83.37 | 98.80% | 1.01 | ||
30 | 0.495% | 201.93 | 99.50% | 1.00 | ||
35 | 0.204% | 489.10 | 99.80% | 1.00 | ||
40 | 0.084% | 1,184.68 | 99.92% | 1.00 | ||
45 | 0.035% | 2,869.47 | 99.97% | 1.00 | ||
50 | 0.014% | 6,950.27 | 99.99% | 1.00 | ||
55 | 0.006% | 16,834.56 | 99.99% | 1.00 | ||
60 | 0.002% | 40,775.74 | 100.00% | 1.00 | ||
65 | 0.001% | 98,764.75 | 100.00% | 1.00 | ||
70 | 0.000% | 239,222.55 | 100.00% | 1.00 | ||
80 | 0.000% | 1,403,467.69 | 100.00% | 1.00 | ||
90 | 0.000% | 8,233,845.64 | 100.00% | 1.00 | ||
100 | 0.000% | 48,306,216.48 | 100.00% | 1.00 |
The 31/37 Odds columns show the odds of never hitting one of your six numbers in that many spins.
The 6/37 Odds columns show the odds of having hit it at least once in that many spins. It's just 1 minus the 31/37 odds.
Note that the items in bold are rounding errors. The odds will never equal 0% or 100%.
I invented a few casino games. Info:
http://www.DaveMillerGaming.com/ —————————————————————————————————————
Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁
October 8th, 2011 at 8:38:46 PM
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Thank you 7craps
Thats a great help
Pando
Thats a great help
Pando