montyace
montyace
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February 17th, 2013 at 11:50:23 PM permalink
Hi all... please can someone help...

If i have a games board with 20 tiles, 8 of them are losing tiles and 12 are winning tiles... to win I need to pick all 12 winners..? What is the probability and odds of guessing all correct winning tiles..? I can calculate for each individual event... like I have 60% chance of picking the first tile correctly... And 55% for the next and so on... but what are the odds of getting all 12 right without picking a loser..??

Help is hugely appreciated... :-)
A Riddle Wrapped In A Mystery Inside An Enigma
sodawater
sodawater
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February 18th, 2013 at 12:17:07 AM permalink
if you have to pick all 12 good tiles in 12 tries, it's easy....


12/20 * 11/19 * 10/18 * 9/17 * 8/16 * 7/15 * 6/14 * 5/13 * 4/12 * 3/11 * 2/10 * 1/9 =

1/125,970
montyace
montyace
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February 18th, 2013 at 12:30:52 AM permalink
Wow .. !! your math looks right ( but what do i know ..? ) but it seems pretty far out there at 1 in 125,970 ..? i cant make that math work .. ? what am i doing wrong with that formula ..???
A Riddle Wrapped In A Mystery Inside An Enigma
sodawater
sodawater
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February 18th, 2013 at 12:33:06 AM permalink
well it's extremely hard to pick all 12 in a row, that's why.

For the math -- Wolfram
montyace
montyace
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February 18th, 2013 at 12:50:05 AM permalink
even bigger wow ..

Stupid question .. but what would 10 in a row be ? given everything else was the same ..?? 12 correct tiles, 8 losers ..20 in total .. but 10 correct pickes ..?
A Riddle Wrapped In A Mystery Inside An Enigma
sodawater
sodawater
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February 18th, 2013 at 12:55:40 AM permalink
Quote: montyace

even bigger wow ..

Stupid question .. but what would 10 in a row be ? given everything else was the same ..?? 12 correct tiles, 8 losers ..20 in total .. but 10 correct pickes ..?



12/20 * 11/19 * 10/18 * 9/17 * 8/16 * 7/15 * 6/14 * 5/13 * 4/12 * 3/11 = 1/2800
montyace
montyace
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February 18th, 2013 at 1:11:34 AM permalink
Thanks very much ..
A Riddle Wrapped In A Mystery Inside An Enigma
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