June 26th, 2012 at 1:02:01 PM
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In Texas Hold'em what are the odds in getting four-of-a-kind provided that the player is holding a pocket pair?
1 in ????? hands
Thanks in advance
1 in ????? hands
Thanks in advance
June 26th, 2012 at 2:33:29 PM
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Assuming you're already holding a pair and stay until the River, I think it's approximately 1 in 123 hands.
Someone else should confirm.
This site says it's 1 in 119 hands: http://www.beatthefish.com/poker-strategy/texas-holdem-odds.html
But until I see the math, I'm going to go with 1 in 123.
Someone else should confirm.
This site says it's 1 in 119 hands: http://www.beatthefish.com/poker-strategy/texas-holdem-odds.html
But until I see the math, I'm going to go with 1 in 123.
June 26th, 2012 at 2:36:42 PM
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I agree with EdCollins. A pocket pair will become quads once every 122.5 times on average.
June 26th, 2012 at 2:38:42 PM
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I get 1 in 122.5 hands.
(2/50)*(1/49)*combin(5,2)
(2/50)*(1/49)*combin(5,2)
June 26th, 2012 at 2:43:43 PM
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That site says you'll flop 4OAK 1 in 119 hands. I have no idea where that number is coming from.
June 26th, 2012 at 3:24:07 PM
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Ah, you're correct. It does say "flop."
I don't know where that number is coming from either. That's way off. It's not nearly that often. I think you'll flop four of a kind, assuming you start with a pair, closer to once every 409 hands.
I don't know where that number is coming from either. That's way off. It's not nearly that often. I think you'll flop four of a kind, assuming you start with a pair, closer to once every 409 hands.
June 26th, 2012 at 3:29:18 PM
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Quote: jc2286That site says you'll flop 4OAK 1 in 119 hands. I have no idea where that number is coming from.
I don't think I can do the math, but I'd bet the the 1 in 119 also includes a singleton being hit by a 3OAK flop even though the site explicitly excludes that possibility in the prose.
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