August 28th, 2010 at 7:45:00 AM
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Just curious as to what the true odds are for getting a RF in JorB when you play perfect strategy vs. when you play just to optimize your chances for a RF (e.g. you are playing in a tournament).
For example, in perfect strategy (which optimizes your expectation) you would always throw away a two card suited royal in favor of a small pair. However, in playing a strategy optimized for a RF, you would always throw away four of a kind in favor of drawing a RF, no matter how remote the chance may be.
For example, in perfect strategy (which optimizes your expectation) you would always throw away a two card suited royal in favor of a small pair. However, in playing a strategy optimized for a RF, you would always throw away four of a kind in favor of drawing a RF, no matter how remote the chance may be.
Prediction is very difficult, especially about the future. - Niels Bohr
August 28th, 2010 at 9:35:47 AM
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I answered that once in an Ask the Wizard column. From memory, the probability was about 1 in 20,000-25,000.
"For with much wisdom comes much sorrow." -- Ecclesiastes 1:18 (NIV)
August 28th, 2010 at 9:49:07 AM
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From halfway down this page.
Quote:I was curious. How do the odds change in video poker if a person always shoots for a natural royal flush? (In other words always holding the most beneficial hadn to obtain a natural royal flush.... disregarding all other possible hands.)
A strategy of going for a royal at all costs, as if all the other hands paid zero, would result in a return of 47.85% on a 9/6 Jacks or Better game. The expected frequency of a royal would increase form once every 40388 hands to once every 23081
“Man Babes” #AxelFabulous
August 28th, 2010 at 4:56:53 PM
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Thanks miplet. According to the reference, the exact answer is:
Once in 40388 hands [optimal strategy] to once every 23081 hands [RF only strategy]
Once in 40388 hands [optimal strategy] to once every 23081 hands [RF only strategy]
Prediction is very difficult, especially about the future. - Niels Bohr