Ultimate Texas Holdem element of risk question
August 23rd, 2011 at 6:57:07 AM
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Hi,
If the element of risk is 2.185% / 4.152252% = 0.526% without playing the optional trips bet. Is the element of risk (2.185 + .9018) / 5.152252 = .599117% with the trips bet (using paytable 1).
Thanks
If the element of risk is 2.185% / 4.152252% = 0.526% without playing the optional trips bet. Is the element of risk (2.185 + .9018) / 5.152252 = .599117% with the trips bet (using paytable 1).
Thanks
August 23rd, 2011 at 1:06:52 PM
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No. The trips bet is a separate wager, not tied to or directly correlated with the Ante/Blind/Raise wager.
The element of risk on the trips bet is always the same as the house edge.
The element of risk on the trips bet is always the same as the house edge.
"Dice, verily, are armed with goads and driving-hooks, deceiving and tormenting, causing grievous woe." -Rig Veda 10.34.4
