January 10th, 2011 at 2:28:18 AM
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What are the odds that myself as a player will have 2 Aces in the Low Hand (and say trips or a straight in the High Hand) and will lose the hand. So therefore the dealer must beat my hand (and have 2 Aces in their Low Hand as well). With only 5 Aces (including the Joker) the odds must be ridiculously high. Or if this is too complicated what are the odds that the Dealer and myself will be able to play 2 Aces up in the Low hand. Thanks.