Craps Repeater Bet - as a table game.

Quote:

O'Sheas has a new table game that I have never seen before. If I had to guess, I think it probably plays like sic bo. If anyone out there has played it, please let me know its concept.

Quote: charliepatrick

Just looking at the 2/12 before 7 (3 for 1) and 3/11 before7 (2 for 1 - i.e. Evens) is terrible House Edge. I can see it as something that would work online, where once the next "game" starts and the rolls can be made automatically, fairly quickly, until the "7 -out"; but the odds need to be better.

Quote: DeMango

How much money for 18 yo's?

Quote: DJTeddyBear

Table 3 is screwed up. You have bet 3 and 4 paying the same and with the same probability and value. The rest of the table is similarly misaligned.

Quote: AlanMendelson

Can we see a wide shot of the table? I'm curious to see where the dice are rolled?

Are they rolled on a traditional table and must hit the back Wall or rolled in a cage or what?

Quote: Wizard

There are a couple pictures in the OP. It seems to be played on a blackjack-size table or maybe a little bigger. I'd lay long odds they use small dice and a shaker, like in pai gow.

Quote: Ace2

Assume there's a fire type bet on the repeater table that pays as follows:

Win all ten repeater bets before rolling a 7: 10000 to 1
Win nine repeater bets before rolling a 7: 3000 to 1
Win eight repeater bets before rolling a 7: 1000 to 1
Win less than eight repeater bets before rolling a 7: Loss

What is the house edge?

Like the fire bet, only distinct wins are counted. So, for instance, if you win the 2 three times, that only counts as one win.

Quote: ThatDonGuy

My Answer

HE = 1 - (53,324,716,837,842,948,521,834,101,764,952,860,337
,479,794,340,838,976,031,734,796,259,597,564,137,929,772,388
,502,720,082,602,106,738,570,389,723,014,763,695,730,257,656
,379,420,034,342,836,497,185,909,061,392,328,048,022,080,590
,390,489,749,983,045,954,828,817,245,768,988,934,637,454,950
,168,370,663,075,325,965,413,107,747,452,805,343,706,609,926
,459,970,444,551,250,523,392,073,018,569,576,096,269,676,229
/
233,473,783,448,792,965,933,524,695,321,952,589,528
,152,298,183,736,457,939,286,839,045,858,409,228,221,650,293
,884,563,811,194,059,089,436,386,958,994,014,107,363,325,671
,964,352,353,886,065,739,979,792,097,652,058,703,112,038,008
,000,165,195,476,192,011,093,871,027,070,114,747,396,048,797
,139,901,142,504,119,068,142,492,631,715,860,366,963,419,710
,442,438,656,000,000,000,000,000,000,000,000,000,000,000,000)
or about 77.1603%

Here is what I think is the Poisson-based method (the above answer is Markov-based):
Define:
P2 = P(2 rolled < 2 times) = e^(-x/36) * (1 + x/36)
P3 = P(3 rolled < 3 times) = e^(-x/18) * (1 + x/18 + (x/18)^2 / 2)
P4 = P(4 rolled < 4 times) = e^(-x/12) * (1 + x/12 + (x/12)^2 / 2 + (x/12)^3 / 6)
P5 = P(5 rolled < 5 times) = e^(-x/9) * (1 + x/9 + (x/9)^2 / 2 + (x/9)^3 / 6 + (x/9)^4 / 24)
P6 = P(6 rolled < 6 times) = e^(-5x/36) * (1 + 5x/36 + (5x/36)^2 / 2 + (5x/36)^3 / 6 + (5x/36)^4 / 24 + (5x/36)^5 / 120)
P7 = P(7 not rolled) = e^(-x/6)

10 wins:
((1 - P2)(1 - P3)(1 - P4)(1 - P5)(1 - P6))^2 * P7

9 wins:
2 P2 (1 - P2) (1 - P3)^2 (1 - P4)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
2 P3 (1 - P3) (1 - P2)^2 (1 - P4)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
2 P4 (1 - P4) (1 - P2)^2 (1 - P3)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
2 P5 (1 - P5) (1 - P2)^2 (1 - P3)^2 (1 - P4)^2 (1 - P6)^2 * P7 / 6
2 P6 (1 - P6) (1 - P2)^2 (1 - P3)^2 (1 - P4)^2 (1 - P5)^2 * P7 / 6

8 wins:
4 P2 (1 - P2) P3 (1 - P3) (1 - P4)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
4 P2 (1 - P2) P4 (1 - P4) (1 - P3)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
4 P2 (1 - P2) P5 (1 - P5) (1 - P3)^2 (1 - P4)^2 (1 - P6)^2 * P7 / 6
4 P2 (1 - P2) P6 (1 - P6) (1 - P3)^2 (1 - P4)^2 (1 - P5)^2 * P7 / 6
4 P3 (1 - P3) P4 (1 - P4) (1 - P2)^2 (1 - P5)^2 (1 - P6)^2 * P7 / 6
4 P3 (1 - P3) P5 (1 - P5) (1 - P2)^2 (1 - P4)^2 (1 - P6)^2 * P7 / 6
4 P3 (1 - P3) P6 (1 - P6) (1 - P2)^2 (1 - P4)^2 (1 - P5)^2 * P7 / 6
4 P4 (1 - P4) P5 (1 - P5) (1 - P2)^2 (1 - P3)^2 (1 - P6)^2 * P7 / 6
4 P4 (1 - P4) P6 (1 - P6) (1 - P2)^2 (1 - P3)^2 (1 - P5)^2 * P7 / 6
4 P5 (1 - P5) P6 (1 - P6) (1 - P2)^2 (1 - P3)^2 (1 - P4)^2 * P7 / 6
(P2 (1 - P3)(1 - P4)(1 - P5)(1 - P6))^2 * P7 / 6
(P3 (1 - P2)(1 - P4)(1 - P5)(1 - P6))^2 * P7 / 6
(P4 (1 - P2)(1 - P3)(1 - P5)(1 - P6))^2 * P7 / 6
(P5 (1 - P2)(1 - P3)(1 - P4)(1 - P6))^2 * P7 / 6
(P6 (1 - P2)(1 - P3)(1 - P4)(1 - P5))^2 * P7 / 6

Multiply the 10-wins value by 10,001
Sum the 9-wins values, and multiply by 3001
Sum the 8-wins values, and multiply by 1001
Add these three values together to get the expected return; HE = 1 - ER

Quote: Ace2

That is the correct answer !

Quote: Ace2

I don’t understand the question

Quote: DeMango

How much money for 18 yo's? now thats funny
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