February 22nd, 2019 at 10:53:54 PM
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The Internet has failed me! What is the probability of getting the Gee Joon tiles in a hand of Pai Gow?
Is it 1 in 5,933?
I hope I don't have to travel all the way to the National Museum of Mathematics for the answer!
Is it 1 in 5,933?
I hope I don't have to travel all the way to the National Museum of Mathematics for the answer!
February 22nd, 2019 at 11:04:11 PM
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There are combin(32,4) = 35,960 possible Pai Gow tiles hands.
And there are combin(2,2)*combin(30,2) = 435 possible hands containing the two Gee Joon tiles.
So, the probability of getting dealt the two Gee Joon tiles is 435 / 35,960 = 3/248.
And there are combin(2,2)*combin(30,2) = 435 possible hands containing the two Gee Joon tiles.
So, the probability of getting dealt the two Gee Joon tiles is 435 / 35,960 = 3/248.