## Poll

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2 votes (40%) | |||

1 vote (20%) | |||

No votes (0%) | |||

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1 vote (20%) | |||

1 vote (20%) | |||

1 vote (20%) | |||

No votes (0%) | |||

1 vote (20%) |

**5 members have voted**

Event | Pays | Count | Probability | Return |
---|---|---|---|---|

Both don't qualify | 0 | 481,649,866,016 | 0.098020 | 0.000000 |

Player 1 wins with 1 | 1 | 9,733,909,104 | 0.001981 | 0.001981 |

Player 1 wins with 2 | 1 | 10,706,973,088 | 0.002179 | 0.002179 |

Player 1 wins with 3 | 1 | 16,528,229,168 | 0.003364 | 0.003364 |

Player 1 wins with 4 | 1 | 28,676,031,164 | 0.005836 | 0.005836 |

Player 1 wins with 5 | 0.50 | 58,484,390,752 | 0.011902 | 0.005951 |

Player 1 wins with 6 | 1 | 84,533,343,740 | 0.017203 | 0.017203 |

Player 1 wins with 7 | 1 | 138,467,802,336 | 0.028180 | 0.028180 |

Player 1 wins with 8 | 1 | 203,945,516,176 | 0.041505 | 0.041505 |

Player 1 wins with 9 | 1 | 326,602,760,752 | 0.066467 | 0.066467 |

Player 1 wins with 10 | 1 | 1,086,260,155,840 | 0.221064 | 0.221064 |

Player 1 outscored | -1 | 905,085,575,368 | 0.184194 | -0.184194 |

Player 1 does not qualify | -1 | 1,058,853,536,752 | 0.215487 | -0.215487 |

Tie | 0 | 504,245,013,984 | 0.102619 | 0.000000 |

Total | 4,913,773,104,240 | 1.000000 | -0.005951 |

I have to respect any game with a house edge of only 0.60%.

Quote:For purposes of the Bonus bet, aces are partially wild. They can be used to complete a straight, flush, straight flush, or royal flush. Otherwise they count as an ace. I know of two pay tables as shown below.

Is that correct, that aces do that? Or is it a typo and the first bolded aces should be joker?

Be fun to have 5 wild cards in a deck, if so. I would enjoy that.

How often do hands with a joker qualify?

How often do hands with a Joker Win 1? Win 0.5? Win 0 (Tie + Both DNQ)? Lose -1?

**********************************

Mathematically this is an interesting game, but from a gameplay point of view it is lame.

- All bets are before any cards are dealt.

- Any 5 card combination will either Not Qualify or have one unique 2 card total.*

So, the entire game is just an elaborate way of assigning a "rank" to a 5 card hand that is completely different than the flush, straight and pairing of conventional poker. But otherwise it is 5 card stud with only one bet -and the one bet is before any cards are dealt.

*Edit: Actually this is not true. Some hands with a joker can be set in different ways such that the two card hand has different point totals. Consider: (Joker) -7-7-6-5. It can be set with 6-5 on top or with 7-7 on top. But certainly all 5 cards hands have one unique maximum 2 card total.

Quote:beachbumbabsIs that correct, that aces do that? Or is it a typo and the first bolded aces should be joker?

Good catch; thanks. I did mean a joker.

Quote:gordonm888Wiz, do you have any way to retrieve stats on Player 1 hands that have a joker?

I did not implicitly calculate joker hands separately. Some coding tweaks and I could tell you but I'm sure having a joker is powerful.

Quote:So, the entire game is just an elaborate way of assigning a "rank" to a 5 card hand that is completely different than the flush, straight and pairing of conventional poker. But otherwise it is 5 card stud with only one bet -and the one bet is before any cards are dealt.

*Edit: Actually this is not true. Some hands with a joker can be set in different ways such that the two card hand has different point totals. Consider: (Joker) -7-7-6-5. It can be set with 6-5 on top or with 7-7 on top. But certainly all 5 cards hands have one unique maximum 2 card total.

I agree this would otherwise* get laughed out of most casinos, but I think this is an old Vietnamese game that has survived the test of time. The way I coded it was to store the score of every possible set of 5 ranks in an array. If there was a joker, it scored it as both 3, 6, and 9 points, and went with the way that maximized the hand value.

* Is this a split infinitive?

As always, I welcome all questions, comments, and especially corrections.

Can you identify a Saigon 5 Card Poker hand which has a joker and no pairs (a joker and four different ranks) and does not qualify?

W, 5,8,T, K (both any 2 non-pair tens)

W, 3, 5, T K

W, 2,3, T, K

W, 3, 9, T K

W, 6, 9, T, K

I realized after I posted the problem, that I had made the mistake of thinking that any two cards with a value of 10 were a pair. It turns out that the problem is easy to solve when there are two cards with the same amount of points.

So let me ask it this way:

Can you identify a Saigon 5-card hand with a joker and 4 cards of different point values that Does Not Qualify? That is, 5 cards that Do Not Qualify consisting of a Joker and 4 different ranks if you count T-K as a single rank?

W, 2, 3, 6, T

W, A,2,3,4