Baccarat Math Question

I am not sure if there is a specific answer to this question but I decided to give it a try anyways. Obviously, the more baccarat hands we play, the closer we will be to the true odds of banker winning 50.7% of hands and player 49.3%. I understand that in the short run, we can easily run into a shoe where player wins significantly more than banker.

I recently played a couple of shoes and decided to bet on banker every single hand from start to finish. The number of player decisions outnumbered banker by 36. I was wondering if there is an average number of shoes where the odds will likely even out so that banker will occur 1.4% more often than player.

The problem with a question like this is, any answer would be the same whether your first shoe had 36 more player decisions than banker or 36 more banker decisions than player. The cards have no memory - and even if they did, (a) how would you know that this particular shoe wasn't "evening out" a previous run of excessive banker wins, and (b) what happens when the table switches to a different shoe? If the specific shoe does not matter, than we have almost certainly almost reached the point of "evening out" as you have to take into account all of the shoes on all of the tables in all of the baccarat games worldwide that have ever been played.

In short, your question doesn't have an answer.

Quote: Donniee

I am not sure if there is a specific answer to this question but I decided to give it a try anyways. Obviously, the more baccarat hands we play, the closer we will be to the true odds of banker winning 50.7% of hands and player 49.3%. I understand that in the short run, we can easily run into a shoe where player wins significantly more than banker.

I recently played a couple of shoes and decided to bet on banker every single hand from start to finish. The number of player decisions outnumbered banker by 36. I was wondering if there is an average number of shoes where the odds will likely even out so that banker will occur 1.4% more often than player.

for maths, i cannot tell.

by my memory, as i checked wizard's data, i found, for about 2200 hands, the player outnumbered more than 100.

to say more, from 1 of wizard's bac data:
25000 shoes,
all are cut into 70 hands:
shoe quantity
player has 1 more 1156
player has 2 more 1255
player has 3 more 1158
player has 4 more 1007
player has 5 more 1006
player has 6 more 811
player has 7 more 700
player has 8 more 686
player has 9 more 617
player has 10 more 499
player has 11 more 419
player has 12 more 320
player has 13 more 291
player has 14 more 234
player has 15 more 170
player has 16 more 145
player has 17 more 92
player has 18 more 76
player has 19 more 52
player has 20 more 37
player has 21 more 28
player has 22 more 17
player has 23 more 12
player has 24 more 11
player has 25 more 9
player has 26 more 4
player has 27 more 1
player has 28 more 2
player has 29 more 1

i did more work on your question, though not direct answer:
if you lose 36 hands by betting banker, if it is by 3 shoes, 70 hands/shoe,
from the bac data, there are 65 times from the 25000 shoes, which will make us lose more than 35 bets given to any 3 continuous shoes.

Not understanding the above. After 25000 shoes what is the final score? B - P - T?

If after almost 2,000,000 decisions, player is ahead, someone check the programming or RNG!