Poker played with 2 decks : Ranking Of Hands

Hi all. I am keen to play poker with 2 decks. I have started to research hand rankings . I dont have the maths capabilities needed to work out the odds so I need to find out from the experts ,like the man who runs this site . I have seen on this site what his rankings are ,and I like them and i am not disputing them .However,on another site, Pagat.com ,is published a table of ranking called the Perl program ,which is quite different. Main points of difference : WOV lists 5's, R/F , Straight flush, 4's and the Perl program lists : 5's , straight flush , 2 pairs flush ,4's , pair flush , flush ,full house . So both tables are worked out by maths geniuses --- which one is right ? Please Help !!

They may both be "right." I don't think there is a "standard" ranking of hands in double-deck poker. Some games may treat, for example, 9-7-7-6-3 of hearts as a better hand than 10-9-7-5-2 of hearts because the first one is a "flush with one pair" and the second one is a "flush with no pairs," while others may treat the second one better because it is a 10-high flush and the other is a 9-high flush.

I had a better idea for a poker game...
Instead, add 13 new cards, 22, 33, 44, 55, 66... and so on.
They count as a pair of the respective cards, but are unsuited.
So you could technically start with 3 of a kind, if you hold AA and Ah (or some other regular ace)
It would add two new hands, five of a kind and six of a kind.
To test it, you could just get 13 cards from another deck and put stickers or permanent marker on them and test it.
Would make the game a whole lot different.

Off the top of my head, the hands are

5oK
RF/SF
Flush w 2 pair
4oK including 2 suited pair
4oK including suited pair
4oK
2 suited pair
Flush w pair
Flush w no pair
Full House w/ suited pair
Full House
straight
3oK w/ suited pair
3oK
Suited Pair
two pair
pair
high card


... but I'm no maths genius, and I probably got a few of the rankings wrong.

I would suggest that there are hands that are not in either of the lists but that are possible and should be considered separately from other hands.

Pretty sure that wilds and bugs change it further.

Quote: uncanny

Hi all. I am keen to play poker with 2 decks. I have started to research hand rankings . I dont have the maths capabilities needed to work out the odds so I need to find out from the experts ,like the man who runs this site . I have seen on this site what his rankings are ,and I like them and i am not disputing them .However,on another site, Pagat.com ,is published a table of ranking called the Perl program ,which is quite different. Main points of difference : WOV lists 5's, R/F , Straight flush, 4's and the Perl program lists : 5's , straight flush , 2 pairs flush ,4's , pair flush , flush ,full house . So both tables are worked out by maths geniuses --- which one is right ? Please Help !!

You can calculate the number of pair flushes and 2 pairs flush and subtract these from the number of flushes given in the Wizard's Multi-Deck Probabilties to make this table:

Hand	Combinations
Royal flush	128
5 of a kind	728
Straight flush	1152
2 PAIRS FLUSH	6864
4 of a kind	87360
PAIR FLUSH	91520
FLUSH W/NO PAIR	163456
Full house	244608
Straight	326400
3 of a kind	3075072
2 pair	5374512
Pair	40909440
Nothing	41681280
total	91962520

Quote: Dieter

Off the top of my head, the hands are

5oK
RF/SF
Flush w 2 pair
4oK including 2 suited pair
4oK including suited pair
4oK
2 suited pair
Flush w pair
Flush w no pair
Full House w/ suited pair
Full House
straight
3oK w/ suited pair
3oK
Suited Pair
two pair
pair
high card...

You forgot Full House with Two Suited Pairs. And that means the FH with one suited pair can be two things: the pair is suited or the trips contains a suited pair.

Is there anything else? I don't think so. But who can remember all those combinations?

Quote: DJTeddyBear

You forgot Full House with Two Suited Pairs. And that means the FH with one suited pair can be two things: the pair is suited or the trips contains a suited pair.

Yes, I realized that late. :)

And yes, it could matter. Consider 8H-8H-8C-6S-6C v 8D-8C-8S-6H-6H - both are 8's full of 6's with a suited pair, and that situation could come up in a game, since there are now 8 cards of each rank. Unfortunately, I think the probability on the "FH w/ 1SP" doesn't make a break one way or the other, so that should be a chop, although I tend to think that most games will agree that in that unusual circumstance, the hand should be awarded to the higher ranking suited pair, and whoever shuffled should be questioned.