Play4fun
Play4fun
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December 3rd, 2012 at 9:18:47 PM permalink
Just started learning the basics of calculating poker odds and most of the examples i've seen for pot odds assume that the player is heads up and all of the players outs are still in the deck. Obviously if you were playing 9-handed, there's a high chance some of your outs are in the hands of folded players. So say you're playing 9 handed and you have a flush draw on the flop, do you consider yourself to have 9 outs for the flush? If so do you calculate your odds of hitting the flush on the turn as 9/(cards in deck) or 9/47 (the amount you'd have in a heads up game)?.

Thanks for clearing this up :)
Play4fun
Play4fun
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December 3rd, 2012 at 9:19:49 PM permalink
edit: double post
rdw4potus
rdw4potus
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December 3rd, 2012 at 9:22:14 PM permalink
Quote: Play4fun

Just started learning the basics of calculating poker odds and most of the examples i've seen for pot odds assume that the player is heads up and all of the players outs are still in the deck. Obviously if you were playing 9-handed, there's a high chance some of your outs are in the hands of folded players. So say you're playing 9 handed and you have a flush draw on the flop, do you consider yourself to have 9 outs for the flush? If so do you calculate your odds of hitting the flush on the turn as 9/(cards in deck) or 9/47 (the amount you'd have in a heads up game)?.

Thanks for clearing this up :)



Yes, you do. Unless you have a reason to actually know information to the contrary (someone folds face up or otherwise flashes their cards, etc.)
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
AxiomOfChoice
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December 3rd, 2012 at 10:16:41 PM permalink
Quote: Play4fun

Just started learning the basics of calculating poker odds and most of the examples i've seen for pot odds assume that the player is heads up and all of the players outs are still in the deck. Obviously if you were playing 9-handed, there's a high chance some of your outs are in the hands of folded players. So say you're playing 9 handed and you have a flush draw on the flop, do you consider yourself to have 9 outs for the flush? If so do you calculate your odds of hitting the flush on the turn as 9/(cards in deck) or 9/47 (the amount you'd have in a heads up game)?.

Thanks for clearing this up :)



This is like saying, there are 30 cards at the bottom of the deck that will never get dealt, and some of them will probably be the suit that you want, so do you really have 9 outs?

The point is, the next card is chosen randomly from the unseen cards. Unless you have a read on your opponent, the fact that your opponent can see them and you can't doesn't matter. There is no difference between the cards in your opponents hands and the cards at the bottom of the deck.
MangoJ
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December 3rd, 2012 at 10:24:59 PM permalink
But what if your out is an Ace. Since most players play AK or maybe AQ, a pre-flop folded hand would mean there is a higher chance the Ace will be left in the deck.
AxiomOfChoice
AxiomOfChoice
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December 3rd, 2012 at 10:27:01 PM permalink
Quote: MangoJ

But what if your out is an Ace. Since most players play AK or maybe AQ, a pre-flop folded hand would mean there is a higher chance the Ace will be left in the deck.



Right. I said, "unless you have a read on your opponent". Being able to cut your opponent down to a range of hands counts as a read.
98Clubs
98Clubs
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December 4th, 2012 at 1:23:34 AM permalink
just a small nit perhaps, the card(s) are drawn off the top of the remaining deck, it may randomly be an out. Nonetheless, the cards are not shuffled to select the next card in B&M poker... there is room for discussion about OLP practices.
Some people need to reimagine their thinking.
MangoJ
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December 4th, 2012 at 4:47:06 AM permalink
Quote: 98Clubs

Nonetheless, the cards are not shuffled to select the next card in B&M poker


Then where is the difference. If the deck is shuffled perfectly random, and you cannot peek at the cards, there is no difference in dealing from a shuffled deck, or shuffleing between each deal.
terapined
terapined
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December 4th, 2012 at 4:06:25 PM permalink
9/47 is correct regardless how many players in. The key is that only 5 cards are known to you, flop and your 2 cards. The rest of the 47 are unknown regardless if they are in the deck or dealt to other players.
When somebody doesn't believe me, I could care less. Some get totally bent out of shape when not believed. Weird. I believe very little on all forums
LonesomeGambler
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December 4th, 2012 at 5:06:03 PM permalink
Quote: terapined

9/47 is correct regardless how many players in. The key is that only 5 cards are known to you, flop and your 2 cards. The rest of the 47 are unknown regardless if they are in the deck or dealt to other players.

This.

MangoJ: you make a good point about high-card outs, since players are often more likely to play high cards than low cards. That's the reason that easily dominated hands like ATo play so poorly out of position. For this reason, it's usually good to discount your outs, which—like most things in poker—requires a little bit of estimation.

For example, if you have AQo on a KQJ two-tone board, you may want to discount your Ace outs, as an Ace suited with the board will complete a Tx straight as well as a flush draw, both rendering your Aces up a losing hand. In this case, I would only count the Ace as 1 or maybe 2 outs rather than 3 simply because I think it's likely that an Ace will help my opponents on a board like this more than it will help me around 33-67% of the time.
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