September 8th, 2010 at 8:19:42 PM
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Which of these two scenarios is more likely to yield a 3 of a kind (and if you could provide the odds on both, that would be great)?
On your first roll, you roll two pair (let's say you need both pair, and we're disregarding the "value" of each of the pairs)..What are the odds of matching up at least one 3 of a kind on the two remaining throws if you:
a. keep both pair aside and roll one die two more times?
or
b. pick up one of the two pairs and roll three dice two times?
Thank you in advance for your help..
- doot
On your first roll, you roll two pair (let's say you need both pair, and we're disregarding the "value" of each of the pairs)..What are the odds of matching up at least one 3 of a kind on the two remaining throws if you:
a. keep both pair aside and roll one die two more times?
or
b. pick up one of the two pairs and roll three dice two times?
Thank you in advance for your help..
- doot
September 8th, 2010 at 11:45:47 PM
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A. The probability of making three of a kind from a two pair would be 1-(4/6)^2=0.555555556
B. The probability of making a three of a kind from a single pair, including a three of a kind in a different number, would be 1-((5/6)^3-5*(1/6)^3)^2=0.691358025
So keep just one pair.
B. The probability of making a three of a kind from a single pair, including a three of a kind in a different number, would be 1-((5/6)^3-5*(1/6)^3)^2=0.691358025
So keep just one pair.
"For with much wisdom comes much sorrow." -- Ecclesiastes 1:18 (NIV)