lottery in different drawing procedure and odds

Let say we have one big mechanical lottery machine, inside have 37 ball numbered from (0 to 36). The machine will draw 5 ball every complete game but each ball is drawn form a pattern like playing baccarat and the last ball place on the middle. The game play more likely playing 2 types of game on every completed game namely baccarat and roulette. NOTE: only one mechanical machine is use.

Each ball is drawn sample: 1st ball is 12 (place on right side same as baccarat where the player side located)
2nd ball is 25 (place on left side same as baccarat where the banker side located)
3rd ball is 15 (place on right side same as baccarat where the player side located)
4th ball is 31 (place on left side same as baccarat where the banker side located)
So this 4 ball is drawn we consider as baccarat accept for the 3rd card for the real baccarat in this case player side having ball point of 12 and 15 result is 7 point in which we disregard every tens, and for banker having ball point of 25 and 31 result is 6 point in which we disregard every tens. In this event right side win that we consider as player bet on baccarat game.

5th ball is 2 (re present as roulette game located in the middle of the 4 was drawn)
So the 5th ball is drawn consider as the winning number for roulette bet. This conclude as a complete game.

HELP and QUESTION

What is the best betting odds for each game (baccarat, and roulette) and house percentage of each.
Baccarat: player, banker, and tie
Roulette: single no.

I was thinking placing each game betting odds

Baccarat: player 1 : 1, banker 1 : 1, and tie 8 : 1 (note on event of tie both player and banker loss half of the original wager)
Roulette: 35 : 1 (single no. same as normal roulette game).
What would be the house edge (house percentage) on each game and each betting area.

Please help

Thanks

Baccarat has drawing rules for the banker that were developed to be the optimal drawing choices with a seen player draw card and an unseen starting player hand from 0 to 7. Would you keep the drawing rules the same, simply using the terminal digit from the lottery balls? If so, this totally changes the odds of the entire game of baccarat, and everything will have to be recalculated.

If you make the drawing/standing rules the same for the player and banker, then it's obvious that the house edge on each bet would be the same. Note you are taking half the bet on ties, which is another rule change from baccarat. To calculate the house edge on baccarat, you'd need to know how often ties come up in this new game for which you haven't fully defined the drawing rules.

For roulette, this is easy to calculate. It's the exact same house edge as normal single-zero roulette.

No drawing rule, just simply use the terminal digit from the lottery balls. For the tie it's just my idea make the house edge a bit higher and actually is not a real baccarat it just look like baccarat in terms of placement of drawn ball and point count on both side.

178057 combinations for Player win
178057 combinations for Banker win
40156 combinations for a tie

-0.0506674742 ev for Banker or Player
-0.08798546446 ev for tie

Thank you very much for your time miplet, I got another question
What if I place additional betting area:

Player Side - Is ODD payout will be less 5%, and if EVEN payout will be less 5%
Banker Side - Is ODD payout will be less 5%, and if EVEN payout will be less 5%

Note: Tie game will not effect this betting odds

thanks again

Quote: 47

Thank you very much for your time miplet, I got another question
What if I place additional betting area:

Player Side - Is ODD payout will be less 5%, and if EVEN payout will be less 5%
Banker Side - Is ODD payout will be less 5%, and if EVEN payout will be less 5%

Note: Tie game will not effect this betting odds

thanks again

Even: 192780 -0.05135135135
Odd: 203490 0.001351351351


All data: 0 v 0 upper left , 9 v 9 lower right , 6 v 3 in yellow