Some advice about lotteries

Hi! Do you have any tips on how to pick 6/48 lottery numbers? I mean tips like the ratio of even numbers and odd numbers (statistics show that 3 even numbers and 3 odd numbers is the most frequent combination - 38 %) or the sum of the winning numbers that has always been between 90 and 220 since the beginning of draws. Do you know eny smart tips like the ones I mentioned?

Thank you

Looking forward to your reply

The odds of picking 1, 2, 3, 4, 5, 6 have the same odds (12,271,512:1) as hitting any other set of numbers.

The distribution of numbers is as follows:

6 odd or 6 even: 134,596 combinations (1.10%)
5 odd / 1 even or 5 even / 1 odd: 1,020,096 combinations (8.31%)
4 odd / 2 even or 4 even / 2 odd: 2,932,776 combinations (23.90%)
3 odd / 3 even: 4,096,576 combinations (33.38%)

The fact that there are less combinations of 6 odds numbers doesn't decrease the odds of one of those sets within those numbers occuring.

The fact that theoretically, 33.38% of numbers picked are 3 odd / 3 even doesn't mean that you should pick 3 odd and 3 even numbers because there are more combinations available.

Now, if your lottery is actually picking a higher percentage (38 - 39%), you might want to look at betting 3 odd / 3 even numbers since this is higher than theoretical. But since you didn't indicate how many draws the percentage was based on, I couldn't tell you whether there is bias on the numbers chosen.

I think the only skill in picking lottery numbers is to choose numbers that are unique from what everyone else chooses. That way if you win, you're less likely to have to split the prize.

As for straegies on how to do this, I've never researched it, but I would think numbers higher than 31 would be good because you avoid dates (birthdays, anniversaries, etc). I might be tempted to go with just a string of numbers like 33,34,35,36,37,38 becuase that seems somehow less likely to win to most people than more "random" numbers, but I might throw one out just in case someone else was doing this. So my advice: 33,34,35,37,38,40. Unfortunately, now that I've posted it, someone may try these exact numbers, so switch it up a little.

dk,

Interesting theory.

I wonder if the quick pickers at the lottery terminals actually pick random numbers or spit out numbers based on an algorithm that would avoid combinations such as 1,2,3,4,5,6. If that were the case, then you could pick numbers that wouldn't be picked by that algorithm and give yourself a bigger chance to win a bigger slice of a pool (even the 5/6 or 4/6 if they were based on a pool).

Quote: boymimbo

I wonder if the quick pickers at the lottery terminals actually pick random numbers or spit out numbers based on an algorithm that would avoid combinations such as 1,2,3,4,5,6.

I no longer play lotteries. When I did I stayed away from consecutive numbers. At the height of my play I pooled money with up to ten other poeple, so we had some picked combos we always used, the rest were quick picks. Once a quick pick given me was 1, 2, 7, 8, 9, 45. That's as close as I ever came to consecutive numbers.

I think the quick pick uses a simple "random" function like that found on most PCs. If they don't often produce consecutive numebrs it may be beacuse they aren't very likely.

BTW I never won anything worth mentioning. I realized I had a better chance to have more money simply by not playing ;)

The fact that theoretically, 33.38% of numbers picked are 3 odd / 3 even doesn't mean that you should pick 3 odd and 3 even numbers because there are more combinations available.

Now, if your lottery is actually picking a higher percentage (38 - 39%), you might want to look at betting 3 odd / 3 even numbers since this is higher than theoretical. But since you didn't indicate how many draws the percentage was based on, I couldn't tell you whether there is bias on the numbers chosen.

It is based on 5 years, one draw a week, it is 260 draws.

Quote: boymimbo

The odds of picking 1, 2, 3, 4, 5, 6 have the same odds (12,271,512:1) as hitting any other set of numbers.

The distribution of numbers is as follows:

6 odd or 6 even: 134,596 combinations (1.10%)
5 odd / 1 even or 5 even / 1 odd: 1,020,096 combinations (8.31%)
4 odd / 2 even or 4 even / 2 odd: 2,932,776 combinations (23.90%)
3 odd / 3 even: 4,096,576 combinations (33.38%)

Sigma squared = np(1-p) = 260 (4096576/12271512)(1-(4096576/12271512)) = 57.818
Sigma = 7.603

Expected 3 odds / 3 evens over 260 draws = 86.788 (87)
Actual 3 odds / 3 evens over 260 draws = 260 * .37 = 96.2 = 97.

Variance = 97 - 86.788 = 10.212 = 1.34 sigmas.

The probability that 97 (37.3%) or more draws out of 260 would have 3 even / 3 odd is 10%.

I don't think however that this is significantly significant. Normally statisticians look to a 5% significance to show a bias. That point is achieved at 100 draws.