james121515
Joined: Jan 2, 2011
• Posts: 7
March 8th, 2012 at 4:38:08 PM permalink
When you a horn high bet that is in increments of \$5, is the amount that goes on the "high" number always \$1? Or is always For example, if you do a \$25 horn hi yo, is it \$6 on the 2, \$6on the 3, \$6 on 12, and \$7 on yo? Or is it \$5 on 2, \$5 on 3, \$5 on 12, and \$10 on yo?
WongBo
Joined: Feb 3, 2012
• Posts: 2126
March 8th, 2012 at 4:45:35 PM permalink
Most common if the number is divisible by five, would be to have three equal bets and one doubled up.
In your example it would be placed as \$5 on each. With \$10 on the high.
Unless you specified it the other way, which would really be a ball busting move which they would try to discourage.
In a bet, there is a fool and a thief. - Proverb.
7craps
Joined: Jan 23, 2010
• Posts: 1977
March 8th, 2012 at 4:59:19 PM permalink
Quote: WongBo

Most common if the number is divisible by five, would be to have three equal bets and one doubled up.

I have never seen a casino allow a horn high that was not divisible by 5.

It keeps the math simple just as WongBo showed.
The high is always doubled up.
Just divide the bet by 5 to get the unit bet for each number

A few examples:
\$35 HH3
35/5 = 7
3 has \$14 and other 3 bets \$7

\$55 HH11
55/5 = 11
11 has \$22 and other 3 bets \$11

\$500 HH12
500/5 = 100
12 has \$200 and other 3 bets \$100

In my dice dealing days, I have booked all these bets and have paid them all.
The \$500 bet hit with a 12 and the high roller was a stiff, never toked.
winsome johnny (not Win some johnny)
Ayecarumba
Joined: Nov 17, 2009
• Posts: 6763
March 8th, 2012 at 5:09:28 PM permalink
Quote: james121515

When you a horn high bet that is in increments of \$5, is the amount that goes on the "high" number always \$1? Or is always For example, if you do a \$25 horn hi yo, is it \$6 on the 2, \$6on the 3, \$6 on 12, and \$7 on yo? Or is it \$5 on 2, \$5 on 3, \$5 on 12, and \$10 on yo?

I typically see it by default as four even bets and the smallest odd left over as the "high" (e.g. \$10 Horn High as 2,2,2,4), but I have also seen it both ways when the chips move from blue to red. The stick will usually ask if the bet gets that big.
Simplicity is the ultimate sophistication - Leonardo da Vinci
james121515
Joined: Jan 2, 2011
• Posts: 7
March 8th, 2012 at 5:22:37 PM permalink
So, in general, if you do a horn high N bet of amount K, and N hits, it pays 30*2(K/5) - 3(K/5) for N = 2, 12 and 15*2(K/5) - 3(K/5) for N = 3, 11. So, \$45 horn hi ace-deuce would pay \$243 if it hits, because you have \$18 on the 3 and \$9 on the other numbers. It would NOT pay \$147, which is what I previously thought (i.e. having \$11 on 2, 11, 12 and \$12 on 3). Right?
guido111
Joined: Sep 16, 2010
• Posts: 707
March 8th, 2012 at 5:24:26 PM permalink
Quote: james121515

For example, if you do a \$25 horn hi yo, is it \$6 on the 2, \$6on the 3, \$6 on 12, and \$7 on yo?
Or is it \$5 on 2, \$5 on 3, \$5 on 12, and \$10 on yo?

The second one is the proper bet that I have seen.

But one can bet exactly how you have divided up the \$25 in your first example.
The stick would just place each amount on each number.

Years ago in Tunica, I watched a dealer place a \$25 horn high 11 by putting \$5 on the 2, 3 and 12 and \$10 on the 11.
The bet lost and no one said anything about it. Seemed to me to be a lot of extra work for the dealer.
7craps
Joined: Jan 23, 2010
• Posts: 1977
March 8th, 2012 at 5:56:20 PM permalink
Quote: james121515

So, in general, if you do a horn high N bet of amount K, and N hits, it pays 30*2(K/5) - 3(K/5) for N = 2, 12 and 15*2(K/5) - 3(K/5) for N = 3, 11.
So, \$45 horn hi ace-deuce would pay \$243 if it hits, because you have \$18 on the 3 and \$9 on the other numbers. It would NOT pay \$147, which is what I previously thought (i.e. having \$11 on 2, 11, 12 and \$12 on 3). Right?

Looks good.
The \$243 assumes the player wants the same bet.
Most times, at that bet amount, the player wants to bet more and maybe even change the high number.
Or he could just ask for the bet to come down. That would be the same total payoff (\$18*15) plus the winning part of the bet (\$18) and down.

I saw one lucky player hit and press the horn high 4 times in a row to the table max. On the 3rd hit of HHYo, he then pressed the HHYo and put \$100 on the Yo. Of course it hit and the TABLE WENT NUTS! The suits were sweating the money.
winsome johnny (not Win some johnny)
james121515
Joined: Jan 2, 2011
• Posts: 7
March 8th, 2012 at 6:05:09 PM permalink
Quote:

But one can bet exactly how you have divided up the \$25 in your first example.
The stick would just place each amount on each number.

Years ago in Tunica, I watched a dealer place a \$25 horn high 11 by putting \$5 on the 2, 3 and 12 and \$10 on the 11.
The bet lost and no one said anything about it. Seemed to me to be a lot of extra work for the dealer.

Wait, so in your opinion it was unusual that the dealer did that? I thought you said that was the proper way. So are you sayig you would have expected him to have done \$8 on 2, 3, 12 and \$11 on 11? To me the math seems so much harder if you do it that way. For example, \$35 horn hi aces doing it that way. Just to figure out how much goes on each number you would have to compute
(35 - 35 mod 4)/4 = 8 for each of the "low" numbers, and then 8 + 35 mod 4 = 11 for the high number. Actually computing the payoff would be even harder.
james121515
Joined: Jan 2, 2011
• Posts: 7
March 8th, 2012 at 6:21:54 PM permalink
Quote:

I saw one lucky player hit and press the horn high 4 times in a row to the table max. On the 3rd hit of HHYo, he then pressed the HHYo and put \$100 on the Yo. Of course it hit and the TABLE WENT NUTS! The suits were sweating the money.

guido111
Joined: Sep 16, 2010
• Posts: 707
March 8th, 2012 at 6:33:42 PM permalink
Quote: james121515

Quote:

But one can bet exactly how you have divided up the \$25 in your first example.
The stick would just place each amount on each number.

Years ago in Tunica, I watched a dealer place a \$25 horn high 11 by putting \$5 on the 2, 3 and 12 and \$10 on the 11.
The bet lost and no one said anything about it. Seemed to me to be a lot of extra work for the dealer.

Wait, so in your opinion it was unusual that the dealer did that? I thought you said that was the proper way. So are you sayig you would have expected him to have done \$8 on 2, 3, 12 and \$11 on 11? To me the math seems so much harder if you do it that way. For example, \$35 horn hi aces doing it that way. Just to figure out how much goes on each number you would have to compute
(35 - 35 mod 4)/4 = 8 for each of the "low" numbers, and then 8 + 35 mod 4 = 11 for the high number. Actually computing the payoff would be even harder.

Most layouts that I have seen have boxes for the 4 horn high bets.
He did not use the box for the horn high 11. It would have been so much easier to put the \$25 there instead of what he did. And most dealers do it that way.