June 13th, 2018 at 12:25:34 PM
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Lucky Shooter side bet is on E-Craps installs from Organic. There was a thread about this in 2016 which was somewhat vague (the exact name wasnt even known) so I decided to make this the official thread with full rules

Before I get to the side-bet let me say a little about the base game. This was an install at Ballys Wild West in AC. Max odds were 2X on BOTH do and dont

Do odds

4 and 10 = 3 for 1

5 anf 9 = 5 for 2.

6 and 8 = 11 for 5

Dont odds

4 and 10 = 3 for 2.

5 and 9 = 5 for 3.

6 and 8 = 11 for 6

For those APs looking to get to Diamond with Doey/Dont the game was rated at $200 per point

Lucky Shooter

Here is the sidebet and paytables at Ballys

Per the other thread there is a higher paytable offering $150 and $1000 for the top 2 wins respectively

Wagers are $1-5 and must be made in conjunction with the pass/dont pass base bet. The sidebet is only available on the comeout

If the initial roll is any Craps (2,3,12) wager is lost

If the initial roll is 7/11 the wager remains but does not win. I.E. you can keep the sidebet wager while removing or not replacing the base bet. However you cannot raise the sidebet if you did not have the max placed without an additional base bet

You may also remove the sidebet at this time

If a point is thrown the side bet is active and locked until a resolution which must occur within the next 6 throws based on the rules

The point of the side bet is to get all the points thrown within the next 6 throws with certain orders established as follows

Succesive throws

1st successive throw:

If any point number OTHER THAN the original point is thrown the wager locks that point and the wager continues.

If a 2,3,7,11,12 or the initiating point is thrown the wager is lost

No payout is made

2nd successive throw:

If any point number OTHER THAN the original point AND the point number thrown in the first successive throw that additional point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point or the point thrown in the first successive throw is thrown then player loses wager

No payout is made

3rd successive throw:

If any point OTHER THAN the original point AND the 2 locked points from the previous successive throws are thrown that point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 2 successive locked points are thrown wager is ended

Payout of 2 for one is made

4th successive throw:

If any point OTHER THAN the original point AND either of the 3 locked successive points are thrown that point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 3 locked successive points are thrown the wager ends

Payout is made for 4 for 1

5th successive throw:

If the remaining point number not thrown appears the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 4 locked successive points are thrown the wager is lost

Payout is made for 10 for 1

6th successive throw:

If the ORIGINAL POINT NUMBER is thrown again on this throw then wager is successfully concluded and player wins jackpot of 500 for 1 (1000 for 1 on some paytables)

If a 2,3,7,11,12 OR any of the 5 locked successive points are thrown the wager is lost

Payout is made for 100 for 1 (150 for 1 on some paytables)

This seems like a horrible bet to me

Im certain the Wizard will enjoy the math breakdown on this one

Before I get to the side-bet let me say a little about the base game. This was an install at Ballys Wild West in AC. Max odds were 2X on BOTH do and dont

Do odds

4 and 10 = 3 for 1

5 anf 9 = 5 for 2.

6 and 8 = 11 for 5

Dont odds

4 and 10 = 3 for 2.

5 and 9 = 5 for 3.

6 and 8 = 11 for 6

For those APs looking to get to Diamond with Doey/Dont the game was rated at $200 per point

Lucky Shooter

Here is the sidebet and paytables at Ballys

Per the other thread there is a higher paytable offering $150 and $1000 for the top 2 wins respectively

Wagers are $1-5 and must be made in conjunction with the pass/dont pass base bet. The sidebet is only available on the comeout

If the initial roll is any Craps (2,3,12) wager is lost

If the initial roll is 7/11 the wager remains but does not win. I.E. you can keep the sidebet wager while removing or not replacing the base bet. However you cannot raise the sidebet if you did not have the max placed without an additional base bet

You may also remove the sidebet at this time

If a point is thrown the side bet is active and locked until a resolution which must occur within the next 6 throws based on the rules

The point of the side bet is to get all the points thrown within the next 6 throws with certain orders established as follows

Succesive throws

1st successive throw:

If any point number OTHER THAN the original point is thrown the wager locks that point and the wager continues.

If a 2,3,7,11,12 or the initiating point is thrown the wager is lost

No payout is made

2nd successive throw:

If any point number OTHER THAN the original point AND the point number thrown in the first successive throw that additional point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point or the point thrown in the first successive throw is thrown then player loses wager

No payout is made

3rd successive throw:

If any point OTHER THAN the original point AND the 2 locked points from the previous successive throws are thrown that point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 2 successive locked points are thrown wager is ended

Payout of 2 for one is made

4th successive throw:

If any point OTHER THAN the original point AND either of the 3 locked successive points are thrown that point number is locked and the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 3 locked successive points are thrown the wager ends

Payout is made for 4 for 1

5th successive throw:

If the remaining point number not thrown appears the wager continues

If a 2,3,7,11,12 or the initiating point OR any of the 4 locked successive points are thrown the wager is lost

Payout is made for 10 for 1

6th successive throw:

If the ORIGINAL POINT NUMBER is thrown again on this throw then wager is successfully concluded and player wins jackpot of 500 for 1 (1000 for 1 on some paytables)

If a 2,3,7,11,12 OR any of the 5 locked successive points are thrown the wager is lost

Payout is made for 100 for 1 (150 for 1 on some paytables)

This seems like a horrible bet to me

Im certain the Wizard will enjoy the math breakdown on this one

Last edited by: darkoz on Jun 13, 2018

For Whom the bus tolls; The bus tolls for thee

June 13th, 2018 at 1:48:43 PM
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there is one hereQuote:darkozLucky Shooter side bet is on E-Craps installs from Organic.

This seems like a horrible bet to me

Im certain the Wizard will enjoy the math breakdown on this one

https://wizardofvegas.com/forum/gambling/craps/28447-interblock-lucky-shooter-craps-sidebet/

let us see who agrees on the results

I also agree with the results when a push is considered as

NOT a bet resolved

event | prob | net | return |
---|---|---|---|

push | 0 | 0 | 0 |

craps | 0.142857143 | -1 | -0.142857143 |

1pt-0 | 0.384920635 | -1 | -0.384920635 |

1pt-1 | 0.265873016 | -1 | -0.265873016 |

1pt-2 | 0.139311434 | -1 | -0.139311434 |

1pt-3 | 0.052646727 | 4 | 0.21058691 |

1pt-4 | 0.012860082 | 14 | 0.180041152 |

1pt-5 | 0.001360855 | 149 | 0.202767435 |

Lucky6 | 0.000170107 | 999 | 0.169936802 |

total | 1 | edge | -0.169629929 |

consider the push as a bet resolved (as in Baccarat)

I show for the pay table -0.131934389 edge

event | prob | net | return |
---|---|---|---|

push | 0.222222222 | 0 | 0 |

craps | 0.111111111 | -1 | -0.111111111 |

1pt-0 | 0.299382716 | -1 | -0.299382716 |

1pt-1 | 0.206790123 | -1 | -0.206790123 |

1pt-2 | 0.108353338 | -1 | -0.108353338 |

1pt-3 | 0.040947455 | 4 | 0.163789819 |

1pt-4 | 0.010002286 | 14 | 0.140032007 |

1pt-5 | 0.001058443 | 149 | 0.157708005 |

Lucky6 | 0.000132305 | 999 | 0.132173068 |

total | 1 | edge | -0.131934389 |

I have played this a few times and think I did ok on it. never hit them all!

they have have a funny way of rolling, not like shoot to win

Sally

added: this pay table (to 1)

-1

0

1

3

9

99

499 (500 for 1)

returns -0.125261435

I used a Markov chain solution in Excel

event | prob | net | return |
---|---|---|---|

push | 0 | 0 | 0 |

craps | 0.142857143 | -1 | -0.142857143 |

1pt-0 | 0.384920635 | -1 | -0.384920635 |

1pt-1 | 0.265873016 | -1 | -0.265873016 |

1pt-2 | 0.139311434 | 1 | 0.139311434 |

1pt-3 | 0.052646727 | 3 | 0.157940182 |

1pt-4 | 0.012860082 | 9 | 0.115740741 |

1pt-5 | 0.001360855 | 99 | 0.134724672 |

Lucky6 | 0.000170107 | 499 | 0.084883347 |

total | 1 | edge | -0.161050417 |

push included

event | prob | net | return |
---|---|---|---|

push | 0.222222222 | 0 | 0 |

craps | 0.111111111 | -1 | -0.111111111 |

1pt-0 | 0.299382716 | -1 | -0.299382716 |

1pt-1 | 0.206790123 | -1 | -0.206790123 |

1pt-2 | 0.108353338 | 1 | 0.108353338 |

1pt-3 | 0.040947455 | 3 | 0.122842364 |

1pt-4 | 0.010002286 | 9 | 0.090020576 |

1pt-5 | 0.001058443 | 99 | 0.104785856 |

Lucky6 | 0.000132305 | 499 | 0.066020381 |

total | 1 | edge | -0.125261435 |

Last edited by: mustangsally on Jun 13, 2018

I Heart Vi Hart

June 13th, 2018 at 2:07:49 PM
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I get a house edge of 7.6% (7.5992 %) on this side bet with the 500, 100,10,4,2 paytable.

So many better men, a few of them friends, are dead. And a thousand thousand slimy things live on, and so do I.

June 13th, 2018 at 2:10:47 PM
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Quote:gordonm888I get a house edge of 7.6% (7.5992 %) on this side bet with the 500, 100,10,4,2 paytable.

That cant be right. The link mustangsally gave worked out to 17% with the higher paytable

Its a complicated bet resolution scheme. You certain you got it all?

For Whom the bus tolls; The bus tolls for thee

June 13th, 2018 at 2:39:05 PM
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at first the rules seems confusingQuote:darkozIts a complicated bet resolution scheme. You certain you got it all?

but the rules are very basic (especially when one plays it)

In CA I saw this machine only at Fantasy Springs Casino a couple years ago

a bit more data

the average number of rolls for any resolution (including a push 7,11)

I get 2.258968717

let us say 2.26

Sally

I Heart Vi Hart

June 13th, 2018 at 5:43:52 PM
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Thanks for bringing this to my attention. I have to rush out the house so can't compare to MS's numbers but here are mine:

Event | Pays | Probability | Return |
---|---|---|---|

Five numbers | 500 | 0.000184 | 0.091879 |

Four numbers | 100 | 0.001632 | 0.163177 |

Three numbers | 10 | 0.007174 | 0.071743 |

Two numbers | 4 | 0.020838 | 0.083352 |

One number | 2 | 0.045010 | 0.090021 |

Zero numbres | 0 | 0.077160 | 0.000000 |

Come out roll 7 or 11 | 1 | 0.222222 | 0.222222 |

Come out roll 2, 3, or 12 | 0 | 0.111111 | 0.000000 |

Point and loss | 0 | 0.514668 | 0.000000 |

Total | 1.000000 | 0.722393 |

“Extraordinary claims require extraordinary evidence.” -- Carl Sagan

June 13th, 2018 at 6:24:54 PM
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Quote:mustangsally

push included

event prob net return push 0.222222222 0 0 craps 0.111111111 -1 -0.111111111 1pt-0 0.299382716 -1 -0.299382716 1pt-1 0.206790123 -1 -0.206790123 1pt-2 0.108353338 1 0.108353338 1pt-3 0.040947455 3 0.122842364 1pt-4 0.010002286 9 0.090020576 1pt-5 0.001058443 99 0.104785856 Lucky6 0.000132305 499 0.066020381 total 1 edge -0.125261435

Maybe I misunderstand the rules, but let me challenge your probability of "1pt-0." I assume this to be when the player makes a point and achieves it the very next roll. I see no other way this event can occur. That said, wouldn't the probability be:

pr(4)^2 + pr(5)^2 + pr(6)^2 + pr(8)^2 + pr(9)^2 + pr(10)^2 = 0.077160494?

“Extraordinary claims require extraordinary evidence.” -- Carl Sagan

June 13th, 2018 at 6:46:06 PM
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Quote:darkozThat cant be right. The link mustangsally gave worked out to 17% with the higher paytable

Its a complicated bet resolution scheme. You certain you got it all?

Sorry, I, too, was going out the door so I basically used Chuckleberry's table of outcome probabilities. I didn't pick up on the fine points of the bet resolution.

So many better men, a few of them friends, are dead. And a thousand thousand slimy things live on, and so do I.

June 13th, 2018 at 7:08:51 PM
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"1st successive throw:Quote:WizardMaybe I misunderstand the rules,

If any point number OTHER THAN the original point is thrown the wager locks that point and the wager continues.

If a 2,3,7,11,12 or the initiating point is thrown the wager is lost"

a 7 or a horn number causes the bet to lose

I played this bet about the time I did the math, so I guess I understood the rules better than those who may have just read them a few times

My transition matrix shows this for Point-0=

3/36*15/36+

4/36*16/36+

5/36*17/36+

5/36*17/36+

4/36*16/36+

3/36*15/36 = 388/1296

Sally

I Heart Vi Hart