Buffalowe
Buffalowe
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Joined: Feb 19, 2018
February 19th, 2018 at 10:02:46 AM permalink
Hey, just made an account to ask this question. I tried looking around for any other discussions about this but couldn't find any. Maybe I didn't look hard enough let me know.

I was playing a 2 dollar minimum bubble Craps machine (Azure shoot to win) and I noticed that on bets where payouts include repeating decimals that the machine rounds up your payout to the nearest penny.

For example, unless I'm mistaken, a 2 dollar bet on a 7:6 payout should be 2.33 repeating, but the machine rounds that up to 2.34 cents. Effectively giving you .66 of a cent extra.

I wasn't exactly sure where this would fit in the house edge equation, can anyone better at this figure out what the house edge would be with the extra penny? I figured that 1 penny on a 2.00 bet would be around half a percent better than the normal odds of -1.51% on the 6 or 8 place.

Or maybe I'm just way off. Thanks in advance.
odiousgambit
odiousgambit
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Joined: Nov 9, 2009
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Buffalowe
February 19th, 2018 at 10:14:16 AM permalink
true odds are 6:5 yielding 11 possibilities

6/11 you lose $2
5/11 you win 2.34

-(6/11*2)+(5/11*2.34) = ev = -0.0272727272727273
-0.0272727272727273/bet = -0.0272727272727273/2 = -0.01363636363636365

I think you were about right but is it of consequence?
the next time Dame Fortune toys with your heart, your soul and your wallet, raise your glass and praise her thus: “Thanks for nothing, you cold-hearted, evil, damnable, nefarious, low-life, malicious monster from Hell!”   She is, after all, stone deaf. ... Arnold Snyder
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