The concept is: Do absolutely nothing on comeout roll until point is established. Therefore you would place no bets but just observe. If point is anything but 4 or 10 also do nothing. If point is 4 or 10 place Dont Pass Line bet with maximum odds plus lay with maximum odds the other number. So if point is 4 lay the 10 and viceversa.
I am not stating that this is a "system" but only an enquiry as to whether the casino would allow it.
I know that many casinos dont like observers with only sporadic bets, so in that case would it then be allowed to place a Pass and Dont Pass Line bet at the same time?
Thank you in advance for your replies.
With this betting pattern even if a dont pass is allowed after the point, the dice goddess will smile upon you and the shooter will throw your non-point 4/10 then make the point.
Once the point is established, you are not allowed to bet the Don't Pass. You are allowed to lay either number and pay a commission on that wager. Given that there is a commission, the casino has an advantage over you, but that is an expected part of the game.Quote: Crapsphanatic... If point is 4 or 10 place Dont Pass Line bet with maximum odds plus lay with maximum odds the other number.
It is not meaningful to refer to "maximum odds" on a lay bet; it is just a lay bet. Odds bets are for Pass, Don't Pass, Come, or Don't Come wagers and may be added after the number for that base wager is established.
On related matters, you are allowed to add a Pass wager after the point is established, because that is to the house's benefit -- you have missed out on your advantage on the come out roll and are at a disadvantage from then on. You are also allowed to take down a Don't Pass wager or a Don't Come wager after the number is established, since that is to the house's advantage also. In summary, they allow you to change Pass/Come/Don't wagers (after the point is established) only in cases where it would be stupid for you to do so.
Where the dice are ice cold
All the dealers are angry
And the servers are old
Yea, I know a casino
Where the players all lose
They hang out there all day
Just to get some free booze
Try playing the Pass
Then switch to the Don't
You can lay all you want
But they still say you won't
Lots of people sit around and only bet/shoot for themselves, I don't see how this is any different. Of course, all it takes is one supervisor having a bad day...
1) Place a Pass and Don't Pass Bet each time on the come-out roll. This will avoid the questioning of whether you can place the Don't Pass after point is established. Yes, I know that they will cancel each other out but that's the whole idea. Yes, I also know, good luck getting the pit boss to let you get away with that for too long but you might be able to make a good argument... before they throw you out.
2) Go Lay the 4 and 10 when one of them is the point.
3) Then go to maximum odds on the Don't Pass. Understandably it's 1:2 but if I am not mistaken Main Street Station goes to 20x Odds and Casino Royale and Eastside Cannery go to 100x Free Odds, so if you load up it "might" work (if Lady Luck is smiling...)
Thoughts?
To figure the house advantage on doey-don't, multiply 1.41 X 2.Quote: Crapsphanatic1) Place a Pass and Don't Pass Bet each time on the come-out roll. This will avoid the questioning of whether you can place the Don't Pass after point is established. Yes, I know that they will cancel each other out but that's the whole idea. Yes, I also know, good luck getting the pit boss to let you get away with that for too long but you might be able to make a good argument... before they throw you out.
The Wizard has it all laid out in the defnitive detail at:
https://wizardofodds.com/games/craps/basics/#toc-DefiningtheHouseEdge
Look at the section on Multi-Roll Bets
Other than some weird looks, I would be surprised if anyone gave you trouble. Casinos really don't make it a habit to stop allowing people to put money on the table. Just steer clear from being that a-hole that cheers loudly during a seven out.
Quote: Crapsphanatic1) Place a Pass and Don't Pass Bet each time on the come-out roll
2) Go Lay the 4 and 10 when one of them is the point.
1) I don't know that any casino will not allow you to bet on both Pass and Don't Pass. The house still has an advantage because you lose when a 12 is rolled.
2) Why not Lay 4 & 10 every time?
Take this to the bank: something on the order of billions of players since Bank Craps was introduced have studied every angle, pondered every nook and cranny, poured over every fact and fallacy, just absolutely bled all over the table in gargantuan efforts to beat the house. So when you come up with the bright idea of hedging the main bets, you can be sure, absolutely sure, that millions of guys have thought of that before and yet they go home just as broke as everybody else.Quote: CrapsphanaticThoughts?
That's why coming to this site is an opportunity to get educated. You will have to be able to be selective; when it comes to Craps, there are members here who will post wildly incorrect stuff. But you will also hear it said that no combination of bets that have a house edge can result in a bet that favors the player. Each bet has an undefeatable Expected Value, and if you combine these bets, you add the EVs into a sum that is the total EV.
Pass and Don't Pass each have a house edge. If you make both bets, you are betting twice as much with not much chance at variance either - the house loves it. Each bet - each - has an undefeatable negative expectation. That you only play the odds on one side [I hope so!] does not make this smarter, instead you are paying more to play.
Quote: SanchoPanzaTo figure the house advantage on doey-don't, multiply 1.41 X 2.
The house edge for pass / don't pass bettor (assuming equal bet amounts) cannot be 1.41 x 2 -- that makes no sense.
A quick approximation is 1 bet out of 72 bets since you lose 1 bet, on average, in 36 rolls but since you are making 2 opposing bets at the same time, the edge is 1 in 72 bets as a guesstimate.
35 times (or 70 bets) that are non-box cars are a wash or net to zero. One bet wins, the other bet loses. It's the box car where one bet loses and one bet pushes, thus losing one bet in 72 bets.
Laying both - you have the same chance of a 4 or a 10 hitting as you do a 7.
Chance of a 4 hitting = 3/36.
Chance of a 10 hitting = 3/36
Chance of either of them hitting = 6/36.
Chance of a 7 rolling = 6/36
Chance of a 7 rolling before a 4 OR a 10 is twice as great.
But basically, you lay 4 and 10, then one hits, you triple the bet (you have to triple in order to cover the loss since it pays only 50%), but you split the increase between the 4 and 10.
Example, $100 on each 4 and 10 lay. a 4 rolls. You triple it it to $300, but since $100 is still on the 10, total is $400 - you split that and so now you have $200 on 4/10 lay. Then another 4 rolls, you triple it ($600), but spread out the total between the two so now you have $400 each. You have now lost $300. If a seven hits, you will win $400. It's kind of a fun martingale variant that spreads the increase and lessons the impact of an exponential increase with each doubling - but maintains the value of martingale system because assuming you still have head room (table limits) and bankroll, you always stay ahead.
Assuming the Lay limit is $5000, you would need to roll six 4/10's before a 7 rolls before running out of room. I guess that is a 2% chance of happening (on the next series) and 99% chance after 1000 rolls.
Quote: VideoBJThe house edge for pass / don't pass bettor (assuming equal bet amounts) cannot be 1.41 x 2 -- that makes no sense.
not only does it make sense, but it is more or less correct...1.41 x 2 = 2.82 but the correct calculation is actually 1.41 + 1.36 since the HE for the dp is 1.36 or 2.78 (with rounding), iow the poster you were responding to had it pretty much correct as both results are of minuscule practical difference...
Quote: VideoBJA quick approximation is 1 bet out of 72 bets since you lose 1 bet, on average, in 36 rolls but since you are making 2 opposing bets at the same time, the edge is 1 in 72 bets as a guesstimate.
35 times (or 70 bets) that are non-box cars are a wash or net to zero. One bet wins, the other bet loses. It's the box car where one bet loses and one bet pushes, thus losing one bet in 72 bets.
but 12 loses on average 1/36 not 1/72 ...1/36 = ta dah! 2.78 (percent)
as others have also pointed out, the doey-don't is two bets, not one thus increasing the overall EV.
tom p