On a 10X $1000 table Max

I'm having some real first world issues Trying to figure out how to max out my bets on this table without trial and definitely without error. A fundamental misunderstanding would hurt substantially. The dealers literally were no help. I did the math ahead of time so,
Here is the question:

I have $115 on the DP and the point is 6.
I LAY $1356 odds.

7-out occurs and pays $115 on the DP and $1130 on the odds.

Is this wrong in any way?

My thoughts are:

"Am I wrong to LAY $1356 odds because its over $1000?"
or
"Am I wrong to expect a $1130 payout because its over $1000? (So, also Had the point been 9, the payout would be only $904)."

So that is my dilemma do I have to downsize my bet here on a six/eight, to $1200?

I believe the table maximum applies to the line bet and any other bet on the table, but not the odds on the line/come bet (which is limited to 10x.)

I'll admit that I don't have much experience with 10x odds, nor with table maximum bets. I know that at a typical 3-4-5x table, the max Don't odds is 6x for every number. My understanding is that the maximum Don't odds is equal to the amount that would be won with max Pass/Come odds.

If you were to bet $115 on Pass/Come at a 10x table, the max odds would be $1150. On a point of 6/8, the Odds bet would win $1380. Therefore, when betting $115 Don't Pass/Come, I believe the max lay odds would be $1380, which would win $1150.

$1356 just needs to be divisible by 6 and less than 1380, and it is

payout of $1130 is correct

I'm guessing the dealers want a bet is more familiar, though, and are bothered by a bet that isn't, and are trying to tell you that by not really answering. Rightside players might normally bet in increments of $50 at such a table, even when going near 10x. A dealer can divide by 5 and mulitply times 6 pretty easy, and know it then for reversing it.

It takes some kind of savant to divide 1356 by 6 - then multiply by 5 - and do it quickly in your head. If it was important to you to lay that exact amount, then I would show your math on paper to the pit boss ahead of time and get him to approve it, and the dealers to expect it.

A dealer can figure it out. 1200 + 120 + 36 pays 1000 + 100 + 30

On the pass line, the limit on the odds is whatever the limit is for the odds. Every bet has a different max bet. The max on the don't pass odds is enough to win as much as the pass line odds can be placed. So if the table limit for PL odds is $1k, you can lay $2000, $1500, or $1200 respectively.

Quote: RS

A dealer can figure it out. 1200 + 120 + 36 pays 1000 + 100 + 30

Such a pleasure having a good dealer like those, and you would think at a place where 10x was allowed, they'd get the better ones .... but the OP did not run into such, doesn't seem, or he was doing something else to tick them off

Quote: RS

A dealer can figure it out. 1200 + 120 + 36 pays 1000 + 100 + 30

While breaking it down like that does make the math easier, it doesn't make it easy.

1,350 would be easier / more intuitive. That breaks down into two common numbers: 1,200 + 150.

Many dealers are trained to think in numbers of chips, rather than the value. Even though it might not look this way on the felt, 1,350 is 12 blacks plus 6 greens. That pays 10 blacks and 5 greens. Oh, sure, they may mentally color it up and pay two purples, one black, one green, but working with chips is easier than working with values.

Thank you very much RS, and everyone. Very helpful. I have to do three formulas instead of 1. crap.