August 27th, 2016 at 8:49:57 AM
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I am not good with math, so can someone assist me in calculating the house edge on a $35 place bet of 12 on a crapless craps game?
On this table the casino offers a free buy of the 12 and pays 6 to 1. You only have to pay a vig when rolled. You can place it for up to $35 and only pay a $1 vig. So essentially a $35 place bet of 12 pays $209. What would the house edge be?
Thanks
On this table the casino offers a free buy of the 12 and pays 6 to 1. You only have to pay a vig when rolled. You can place it for up to $35 and only pay a $1 vig. So essentially a $35 place bet of 12 pays $209. What would the house edge be?
Thanks
August 27th, 2016 at 9:22:06 AM
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Let's walk through it so you can get better.
First question: What's the probability of winning? Of losing?
First question: What's the probability of winning? Of losing?
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice."
-- Girolamo Cardano, 1563
August 27th, 2016 at 1:26:18 PM
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It is a buy bet. Not aware of any casino that doesn't buy at $20. The real question is; vig on win or up front? On win, it will be the lowest vig, bet on the table, outside of odds. I'm sure ME will give you that number.
Nothing like the stupidity of offering free buys on the 4, 5, 9, and 10, and taking vig up front on the 2, 3, 11, and 12.
Nothing like the stupidity of offering free buys on the 4, 5, 9, and 10, and taking vig up front on the 2, 3, 11, and 12.
When a rock is thrown into a pack of dogs, the one that yells the loudest is the one who got hit.
August 27th, 2016 at 3:27:11 PM
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Quote: dustin88bdI am not good with math, so can someone assist me in calculating the house edge on a $35 place bet of 12 on a crapless craps game?
On this table the casino offers a free buy of the 12 and pays 6 to 1. You only have to pay a vig when rolled. You can place it for up to $35 and only pay a $1 vig. So essentially a $35 place bet of 12 pays $209. What would the house edge be?
Thanks
For the benefit of others, the bet is that a 12 will be rolled before a 7.
There is one way to roll a 12 and six ways to roll a 7. So the probability the 12 will come first is 1/7.
Expected return =[ (1/7)*209 + (6/7)*-35 ]/35 = -1/35 = -1/245 = -0.41%.
So the house edge = 0.41%.
"For with much wisdom comes much sorrow." -- Ecclesiastes 1:18 (NIV)