Overall HE if i do both pass + place bets?

3/4/5x odds, $10min

pass/continuous come + max odds

after I recouped the $ I have on the table (5 hits), I start pressing.
but instead of pressing the Come bet, I alternate Placing $30 on the 6 or 8 no matter which # was hit.

so if I have $10pass/$50 odds on the 6 plus Place the 6 for $60, then my HE is just the avg of the 2?

(.37% + 1.52%)/2 = .95%?

so basically if my Place bet > $120, then I might as well play Baccarat?
(HE for banker = ~1.05%)

Quote: 100xOdds

3/4/5x odds, $10min

pass/continuous come + max odds

after I recouped the $ I have on the table (5 hits), I start pressing.
but instead of pressing the Come bet, I alternate Placing $30 on the 6 or 8 no matter which # was hit.

so if I have $10pass/$50 odds on the 6 plus Place the 6 for $60, then my HE is just the avg of the 2?

(.37% + 1.52%)/2 = .95%?

so basically if my Place bet > $120, then I might as well play Baccarat?
(HE for banker = ~1.05%)

This is most easily done with edge per roll and a weighted average for total edge per roll. And the answer depend on:

$10 on the 4/10: does it pay $18 or $19? Edge per resolution of 6.66% or 3.33% divided by four rolls = 1.666% per roll versus 0.8325% per roll and goes down to 0.4166% per roll for $20 buy.
$10 on the 5/9: edge per roll is 1.11%
$12 on the 6/8: edge per roll is 1/66 or 1.51% divided by (36/11) rolls 0.46296% per roll

Once you memorize the 1.66%, the 0.8325%, the 0.4166%, the 1.11%, the 0.46296% and the 0.41% for the pass line, you just modulate each percentage by the bet amounts on each bet to get the average COST per roll.

Then you take the COST per roll and divide that by the total amount of bets on the felt. That's you weighted edge per roll for the combination of bets.

So $66 across has a cost of $20 * 0.8325% + $20 * 1.11% + $24 * 0.46296% =

$0.1665 per roll for the 4/10
$0.2222 for the 5/9
$0.1111 for the 6/8
=======
$0.4998 or $0.50 per roll

$0.50 / $66 = 0.75% weighted edge per roll for $66 across

The lowest edge per roll for the across in percentage basis is $160 across -- the cost on the four and ten is still $0.1665 per roll, but you get bigger action for the exact same cost which reduces your percentage edge.

0.75% per toss of the dice (the random event) is cheaper than Baccarat. It just goes faster. And you have to redefine the "bet" as the throw of the dice (IE: the random event, not the markings on the felt where you put chips).

Of course the cheapest way to play the game is max lay odds (or what you can afford) with a single don't pass bet. That's in the FAQ. The only exception would be on a $25 table where it's cheaper to buy the four than to bet the pass line or don't with no odds.

Quote: Ahigh

So $66 across has a cost of $20 * 0.8325% + $20 * 1.11% + $24 * 0.46296% =

$0.1665 per roll for the 4/10
$0.2222 for the 5/9
$0.1111 for the 6/8
=======
$0.4998 or $0.50 per roll

$0.50 / $66 = 0.75% weighted edge per roll for $66 across

Do you mean $64 = $20*0.8325% + $20*1.1111% + $24*0.4629% = $0.4998/roll and $0.4998/$64 = 0.78094% weighted edge/roll for $64 across?

I get it. You guys know now that deriving the HE in *bet combinations*, esp per roll, drives me bat-s*** crazy, so you have gotten together to send me to the funny farm!