Question on Payouts

I have a stupid question that I think I know the answer too.

On a 3-4-5 table I place 15$ on the pass line. The dice turn up 6. I put full 5x odds on it for a total of 90$ on the table. The 6 comes up again. The payout for a 6 is 6/5 right? So I won 105$ plus I get my 90$ back.

So is the proper way to calculate a Payout

B+B*O*P

B = Initial Bet
O = Odds on Bet
P = Payout on Bet

Sorry for the silly question. I only ask because I am trying to write a program, and it works perfectly till I start adding in odds and payouts.

Thanks for the help.

seems to me that formula assumes you take full odds

Your right. I think I would need to write it like

(B+B*O)*P

To account for 0 odds taken.

Thank you for the insight.

>On a 3-4-5 table I place 15$ on the pass line. The dice turn up 6. I put full 5x odds on it for a total of 90$ on the table.
You have a PassLine bet of 15 and you have an OddsBet of 75. Your two separate and distinct bets add up to 90 of your money on the table.
>The 6 comes up again.
>The payout for a 6 is 6/5 right? So I won 105$ plus I get my 90$ back.
NO.
The payout for your line bet is 1:1 which means you receive 15 and retain your original line bet of 15.
The payout for your OddsBet is 6:5 which means you receive 90 and retain your original odds bet of 75.

>So is the proper way to calculate a Payout
Is to calculate the ODDS BET Payout
and then
To calculate the Line Bet Payout,
but to at all times realize that there are two separate and distinct bets that are at all times calculated and paid separately.

If you want to add up the money mentally in to one total, that is fine... dealers will often pay that way to save chips and hand moves, but usually dealers must pay an odds bet first and then pay the line bet.

Your math totals are correct but neither a computer program nor a dealer will be paying anything but the two separate and distinct bets. So keep them separate and distinct in your program and add the totals if you must.

This one is kind of an easy one. I believe I read somewhere that some player wanted the 3x4x5x odds deal set up so that the payoffs would be easy for him to figure out.

The easy way is: The total amount paid is 7X the original line bet. In your case, 7X $15 = $105. Do it if the point were a 10. You would have $15 PL and $45 Odds. Therefore, once again 7X $15 = $105 ($90 at 2:1 for the odds and $15 for the PL.)

FleaStiff is correct. They are two distinct payoffs, but if you want to calculate quickly what your payout should be, just multiply the line bet by 7.

Quote: bushman

I believe I read somewhere that some player wanted the 3x4x5x odds deal set up so that the payoffs would be easy for him to figure out.

Quite right. And when the casino big wigs realized how fast and easy it was, it spread like wild fire to other casinos. Players may or may not have loved it, but casinos sure did simply because to the casino time is money and anything that simplifies payouts makes it faster and less prone to error.

Quote: bushman

The easy way is: The total amount paid is 7X the original line bet.

YES. Though its best to remember: You will not always be at a 3x4x5x table and computer programs do sometimes need revision. So keep your thoughts and your computer programs revisable by keeping straight in your mind that it is two separate bets involved.

Quote: bushman

FleaStiff is correct.

He always is. He is always a modest fellow too.

Quote: bushman

They are two distinct payoffs, but if you want to calculate quickly what your payout should be, just multiply the line bet by 7.

Yes. A 3x4x5x table works out to being only slightly different than a 5x table except for speed and ease of confirming proper payments.

Quote: FleaStiff

YES. Though its best to remember: You will not always be at a 3x4x5x table and computer programs do sometimes need revision. So keep your thoughts and your computer programs revisable by keeping straight in your mind that it is two separate bets involved.

Keep the code simple and dynamic. Agree.

Quote: FleaStiff

He always is. He is always a modest fellow too.

Agree, once again. He is always correct, he is very modest, but most importantly, he is always good for a chuckle. Thanks for giving me a chuckle at the start of the day.

Quote: FleaStiff

>On a 3-4-5 table I place 15$ on the pass line. The dice turn up 6. I put full 5x odds on it for a total of 90$ on the table.
You have a PassLine bet of 15 and you have an OddsBet of 75. Your two separate and distinct bets add up to 90 of your money on the table.
>The 6 comes up again.
>The payout for a 6 is 6/5 right? So I won 105$ plus I get my 90$ back.
NO.
The payout for your line bet is 1:1 which means you receive 15 and retain your original line bet of 15.
The payout for your OddsBet is 6:5 which means you receive 90 and retain your original odds bet of 75.

>So is the proper way to calculate a Payout
Is to calculate the ODDS BET Payout
and then
To calculate the Line Bet Payout,
but to at all times realize that there are two separate and distinct bets that are at all times calculated and paid separately.

If you want to add up the money mentally in to one total, that is fine... dealers will often pay that way to save chips and hand moves, but usually dealers must pay an odds bet first and then pay the line bet.

Your math totals are correct but neither a computer program nor a dealer will be paying anything but the two separate and distinct bets. So keep them separate and distinct in your program and add the totals if you must.

Wow thanks a ton. I guess it is good that I asked then, because I only knew the totals not how the payouts were actually calculated.

That helps so much thank you FleaStiff