2 Crap bets
October 4th, 2012 at 11:25:59 AM
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I have a question about placing the 6 and 8. I know if I place one of them the casino vig is 1.52. What is the casino vig if I place both? Is there any 2 bets that will reduce the casino vig? Or is it best to only bet one bet at at time.
October 4th, 2012 at 11:35:06 AM
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Quote: urbfloramsI have a question about placing the 6 and 8. I know if I place one of them the casino vig is 1.52. What is the casino vig if I place both? Is there any 2 bets that will reduce the casino vig? Or is it best to only bet one bet at at time.
The term vig, is usually associated to an amount the casino charges you (usually 5%) either when you make the bet, or win you win a bet.
The 1.52% you are referencing for the Place 6 is the House Edge. aka HE
Interesting question. . What makes you think the HE would be anything different?
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October 4th, 2012 at 11:36:02 AM
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Quote: urbflorams"What is the casino vig if I place both?"
House edge for BOTH made at the same time will be the same per decision.
They are still 2 separate bets that do resolve at different times.
https://wizardofvegas.com/forum/off-topic/general/9949-place-betting-6-and-8-together/
But, The Expected Value will be higher for both
while the standard deviation is a bit lower compared to just the two bets individually.
Are there any?Quote: urbflorams"Is there any 2 bets that will reduce the casino vig?"
You mean the combined house edge for multiple bets made and resolved.
Yes, many.
Line bets at 1.4% and odds bets at 0%.
Quote: urbflorams"Or is it best to only bet one bet at at time"
Depends only on why you play.
What do you mean by "Best"?
Do not get stuck on house edge only.
Some house edge values that look lower actually have the same or higher EV than higher HE values.
It is the comparison of bets that resolve per roll, per decision not counting pushes and per decisions counting pushes.
One needs to compare apples to apples.
The EV (expected value or expected loss)
is very useful data and when combined with standard deviation over actual number of bets
will paint a very nice picture of what that or any style of play can end up at.
I am sure your questions are just general and you must have a very specific question to ask based on the Place bets.
winsome johnny (not Win some johnny)
October 5th, 2012 at 8:28:39 AM
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This has got to be one of the most recurring discussions ever.
If you take them both down on the win and go home, and you only ever anticipate a single event, the house edge can be considered to go lower.
Similarly, all the house edges are rated "per event" where an event lasts for multiple rolls.
The event for a 6 or an 8 before a seven has 16 ways to resolve and 20 ways to push.
The average number of rolls is for one of these 16 outcomes is 36/16 or 2.25.
The average number of rolls for a place bet on the six is the same as the average number of rolls for a place bet on the eight, which is 3.2727
The edge per roll is known to be .464
So the number of rolls can go down if you walk on the first hit or less. Which lowers the house edge if you accept the lower number of rolls being 2.25 instead of 3.27272
That means you can get .464 * 2.25 house edge or 1.04% instead of .464 * 3.2727 or 1.518%
People argue just about every week here about this topic and do much more complicated explanations for why they are right though. It seems to be a fun thing for people to do I guess.
Thank you drive through!
If you take them both down on the win and go home, and you only ever anticipate a single event, the house edge can be considered to go lower.
Similarly, all the house edges are rated "per event" where an event lasts for multiple rolls.
The event for a 6 or an 8 before a seven has 16 ways to resolve and 20 ways to push.
The average number of rolls is for one of these 16 outcomes is 36/16 or 2.25.
The average number of rolls for a place bet on the six is the same as the average number of rolls for a place bet on the eight, which is 3.2727
The edge per roll is known to be .464
So the number of rolls can go down if you walk on the first hit or less. Which lowers the house edge if you accept the lower number of rolls being 2.25 instead of 3.27272
That means you can get .464 * 2.25 house edge or 1.04% instead of .464 * 3.2727 or 1.518%
People argue just about every week here about this topic and do much more complicated explanations for why they are right though. It seems to be a fun thing for people to do I guess.
Thank you drive through!
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