Quote:railerDoes the Expectation for "Hit" assume one card and one card ONLY is drawn by the player? Thanks.

I believe that is the final expectation of the hand and does not assume a single hit.

Quote:DRichI believe that is the final expectation of the hand and does not assume a single hit.

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That is correct. It assumes the play follows optimal strategy the rest of the hand, after the play in question.

Quote:WizardThat is correct. It assumes the play follows optimal strategy the rest of the hand, after the play in question.

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That's really impressive.

So if I understand this correctly, ...the expectation*probability is calculated for the player hand being hit once with every possible card... then the program calculates the expectation and probability of each decision point (hit or stand) after that... choosing the best decision given the remaining subset of cards?

Quote:railerQuote:WizardThat is correct. It assumes the play follows optimal strategy the rest of the hand, after the play in question.

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That's really impressive.

So if I understand this correctly, ...the expectation*probability is calculated for the player hand being hit once with every possible card... then the program calculates the expectation and probability of each decision point (hit or stand) after that... choosing the best decision given the remaining subset of cards?

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Yes. That's correct. It is one of two internet BJ hand calculators that do this. The other one is bjstrat. The answers between the two calculators have been extensively checked and are equivalent. Wizard's calculator provides 6 digits of accuracy to the right of the decimal point, whereas the bjstrat calculator only provides 4 digits. The bjstrat calculator does provide some other output information not available on the Wizard's calculator, such as probability of dealer outcomes.

Quote:railerSo if I understand this correctly, ...the expectation*probability is calculated for the player hand being hit once with every possible card... then the program calculates the expectation and probability of each decision point (hit or stand) after that... choosing the best decision given the remaining subset of cards?

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That's right.