jjcmend
jjcmend
Joined: Feb 27, 2014
  • Threads: 1
  • Posts: 1
February 27th, 2014 at 2:30:59 PM permalink
Here in some non-Indian California casinos, there's a rule where the player can surrender at anytime in their play (such as a 3 or 4 card 16 against an A). Although the other rules tend to be quite terrible, e.g. 6-5 BJs, I was wondering if anyone could calculate what this rule reduces the house edge by. I am simple curious from a mathematical standpoint. Thanks!
Sonuvabish
Sonuvabish
Joined: Feb 5, 2014
  • Threads: 29
  • Posts: 1342
February 27th, 2014 at 2:41:40 PM permalink
Quote: jjcmend

Here in some non-Indian California casinos, there's a rule where the player can surrender at anytime in their play (such as a 3 or 4 card 16 against an A). Although the other rules tend to be quite terrible, e.g. 6-5 BJs, I was wondering if anyone could calculate what this rule reduces the house edge by. I am simple curious from a mathematical standpoint. Thanks!



Approx. .12%. Regular surrender is .08%.

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