Here in some non-Indian California casinos, there's a rule where the player can surrender at anytime in their play (such as a 3 or 4 card 16 against an A). Although the other rules tend to be quite terrible, e.g. 6-5 BJs, I was wondering if anyone could calculate what this rule reduces the house edge by. I am simple curious from a mathematical standpoint. Thanks!
Approx. .12%. Regular surrender is .08%.