shaned9
shaned9
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January 15th, 2012 at 10:06:11 AM permalink
Hey there, I've tried but I cannot figure out this math question and I was hoping you could answer it for me. Hopefully you can and will help me.

You have a 10 team league and all the teams are equal. The league has been around for 18 seasons. 1 team has won the league 10 of 18 seasons. What are the odds or probability of that happening? How many championships should each team have won if again they're all considered equal.

My thoughts are the answer to the 2nd question is 1.8 times.

But I'm really not terribly sure about any of this.

Please help me. Thanks
thecesspit
thecesspit
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January 15th, 2012 at 10:17:46 AM permalink
If all teams are equal, then each team should have a 10% shot of winning the league each season.

Winning 10 out of 18 10% shots (exactly) is given by the binomial distribution equation. http://stattrek.com/tables/binomial.aspx

For exactly 10 wins : 1.883638417518E-06 (which better written is) : 0.00000188 or 1 in 531,914.

For 10 or more wins : 0.00000204 or 1 in 490,196

My suggestion would be that all teams are not exactly equal.

(Edit : apologies, missing a 0 in my first answer, corrected the typo)
"Then you can admire the real gambler, who has neither eaten, slept, thought nor lived, he has so smarted under the scourge of his martingale, so suffered on the rack of his desire for a coup at trente-et-quarante" - Honore de Balzac, 1829
odiousgambit
odiousgambit
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January 15th, 2012 at 10:22:37 AM permalink
Assumption all along is that teams are assumed equal in talent, that someone winning is a random result, it seems.

you don't have simplicity because it isn't about a team *never* winning or *always* winning. Someone will enlighten us. edit: Cesspit did.
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robsanchez
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January 15th, 2012 at 6:49:27 PM permalink
This has to be an interesting thought about the calculations here. I just hoped that things would really work out well in the long run for this one. Have to really observe a lot of things while doing your sports betting.
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boymimbo
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January 15th, 2012 at 9:41:20 PM permalink
The probability of a team winning 10 times in 18 seasons is:

18! / (18-10)!10! * (0.1^10)*((0.9)^(18-10)) = .00000188364.

And of course, if all teams are equal, each team should have won the championship 1.8 times.
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shaned9
shaned9
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January 19th, 2012 at 1:23:20 PM permalink
I have a follow up question now. And thanks for your math skills. It is way beyond my scope.

Same basic paremeters.

10 teams
18 seasons
6 teams make the playoffs each year
1 team has made the playoffs all 18 years
All teams are assumed equal.

What are the odds of that happening?

Thanks.
rdw4potus
rdw4potus
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January 19th, 2012 at 1:36:46 PM permalink
Quote: shaned9

I have a follow up question now. And thanks for your math skills. It is way beyond my scope.

Same basic paremeters.

10 teams
18 seasons
6 teams make the playoffs each year
1 team has made the playoffs all 18 years
All teams are assumed equal.

What are the odds of that happening?

Thanks.



There's a 60% chance of making the playoffs each year? That'd make it .6^18=.0001016, or 1:9846.

Why are we assuming all teams are equal? Among other things, that would seem to suggest that your league lacks the appropriate amount of smacktalk:-)
"So as the clock ticked and the day passed, opportunity met preparation, and luck happened." - Maurice Clarett
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