sharkbyte
Joined: Feb 14, 2011
• Posts: 8
February 15th, 2011 at 5:50:58 PM permalink
Could they reduce the house edge, through bet progressions, while staying within normal table limits?

"You don't need to win every spin, just the ones you bet on."

I have a progression, betting through 15 spins, that seems to reduce the overall house advantage to 1.73%.

2 different tests:

1st Million Spin Test
16368 progression losses
947360 decisions

2nd Million Spin Test
16377 progression losses
947373 decisions

Any thoughts? Anyone have test results showing comparable or better results?
teddys
Joined: Nov 14, 2009
• Posts: 5444
February 15th, 2011 at 5:54:48 PM permalink
No, no system can reduce the house edge. The fact that you got a 1.73% negative return is just a function of luck/variance/whatever you want to call it.

How did you come up with 1.73% anyway?
"Dice, verily, are armed with goads and driving-hooks, deceiving and tormenting, causing grievous woe." -Rig Veda 10.34.4
sharkbyte
Joined: Feb 14, 2011
• Posts: 8
February 15th, 2011 at 6:09:00 PM permalink
Quote: teddys

The fact that you got a 1.73% negative return is just a function of luck/variance/whatever you want to call it.

I disagree. 2 sets of spins, with 950k decisions each, and with results within .01% of each other. If this is luck, or variance, how many spins before the numbers can be considered legitimate?

Quote: teddys

How did you come up with 1.73% anyway?

Your question makes me think I used incorrect terminology, and we are discussing differing percentages. But, to answer your question, I simply took [# of losing progressions] / [total decisions].
MathExtremist
Joined: Aug 31, 2010
• Posts: 6526
February 15th, 2011 at 6:21:19 PM permalink
Quote: sharkbyte

I disagree. 2 sets of spins, with 950k decisions each, and with results within .01% of each other. If this is luck, or variance, how many spins before the numbers can be considered legitimate?

Your question makes me think I used incorrect terminology, and we are discussing differing percentages. But, to answer your question, I simply took [# of losing progressions] / [total decisions].

Number of losing progressions doesn't matter, only number of dollars won and the percentage of total wagers that represents. What did your bankroll do over your two million trials? Up or down?
"In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice." -- Girolamo Cardano, 1563
sharkbyte
Joined: Feb 14, 2011
• Posts: 8
February 15th, 2011 at 6:38:39 PM permalink
Quote: MathExtremist

Number of losing progressions doesn't matter, only number of dollars won and the percentage of total wagers that represents. What did your bankroll do over your two million trials? Up or down?

The overall result was a loss. Wasn't trying to imply that it won. However, I realized what was being looked for and the overall rate works out to -5.17% and -5.18% respectively. Not being a numbers expert, I would guess these fall within 1 standard deviation of the expected -5.26%.
P90
Joined: Jan 8, 2011